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zzz [600]
3 years ago
5

A spring-loaded pellet gun is designed to fi re 3.00-g projectiles horizontally at a speed of 45.0 m/s. (a) If the spring is com

pressed to its maximum design difference of 8.00 cm, what spring constant is required?
Physics
1 answer:
taurus [48]3 years ago
3 0

Answer:

The spring constant required = 949.2 N/m

Explanation:

The energy stored in the spring is converted to kinetic energy of the projectiles fired.

Energy stored in spring's = kx²/2

Kinetic energy of bullets = mv²/2

k = spring constant = ?

x = maximum compression of the spring = 8 cm = 0.08 m

m = mass of projectiles fired = 3.0 g = 0.003 kg

v = velocity of projectiles fired = 45.0 m/s

kx² = mv²

k (0.08²) = 0.003 (45²) = 6.075

k = 949.2 N/m

The spring constant required = 949.2 N/m

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Answer:

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The potential energy of that hammer is a function of its displacement against gravity. Considering that it fell with a velocity of 12 m/s, it was its displacement against gravity that gave it this velocity. It will continue to move until its displacement to gravity is zero.

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