Question

t the equator, near the surface of Earth, the magnetic field is approximately 50.0 μT northward and the electric field is about 100 N/C downward in fair weather. Find the gravitational, electric, and magnetic forces on an electronwith an instantaneous velocity of 6 x106m/s directed to the east in this environment

Answer 1

Answer:

Explanation:

Given that,

Magnetic field B = 50.0 μT

B = 50 ×10^-6 T

Electric field E = 100N/C

Instantaneous speed of electron

V = 6×10^6 m/s

Charge of an electron

q = 1.609×10^-19C

Mass of an electron is

m = 9.11×10^-31kg

A. Formula to calculate the gravitational force is given as

F = mg

F = 9.11×10^-31 × 9.81

F = 8.94 × 10^-30 N.

The gravitational force is 8.94×10^-30 N upward

B. Formula to calculate the electric force is given as

F = qE

F = 1.609 × 10^-19 × 100

F = 1.609 × 10^-17 N.

The electric force is 1.609 × 10^-17 N, upward

C. Formula to calculate the magnetic force is given as

F = qVB

F = 1.609 × 10^-19×6×10^6×50×10^-6

F = 4.83 × 10^-17 N

The magnetic force is 4.83×10^-17N, downward