The number of atoms present in 0.58 mole of magnesium, Mg is 3.49×10²³ atoms
<h3>Avogadro's hypothesis </h3>
1 mole of Mg = 6.02×10²³ atoms
<h3>How to determine the atoms in 0.58 mole of Mg </h3>
1 mole of Mg = 6.02×10²³ atoms
Therefore,
0.58 mole of Mg = 0.58 × 6.02×10²³
0.58 mole of Mg = 3.49×10²³ atoms
Thus, 3.49×10²³ atoms are present in 0.58 mole of Mg
Learn more about Avogadro's number:
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Answer:
a) 6312.12 lbm
b) D = 11.843 inch
Explanation:
GIVEN DATA:
Height of person = 1.89 m = 74.41 inch
mass of person m = 89 kg = 196.211 lbm
a) person earth weight =mg
where g is acceleration due to gravity = 32.17 ft/sec^2
b) waist to height ratio = 0.5
circumference of waist =
=37.21 inch
we know that circumference is given as 
D = 11.843 inch
Answer: d
Explanation:
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alternative acids are more cost-effective and allow for flavor expression through nontraditional methods and ingredients, making for increased versatility.
Since the compound is 72.2% Mg then there would be 27.8% N. Then you can just change it to 72.2 g Mg and 27.8 g N.
then convert to moles by dividing by molecular mass.
72.2÷24.31=2.96 moles Mg
27.8÷14.01=1.98 moles N
then divided by the lowest number.
2.96÷1.98=1.5
Since it is 1.5 you multiply by 2. so you have 3 Mg
1.98÷1.98=1 N
so the empirical formula is Mg3N
