<u>Answer: </u>The molar mass of solute is 115 g/mol.
<u>Explanation:</u>
Elevation in the boiling point is defined as the difference between the boiling point of the solution and the boiling point of the pure solvent.
The expression for the calculation of elevation in boiling point is:
OR
......(1)
where,
Boiling point of pure solvent (benzene) = 
Boiling point of solution = 
i = Vant Hoff factor = 1 (for non-electrolytes)
= Boiling point elevation constant = 
= Given mass of solute = 10 g
= Molar mass of solute = ? g/mol
= Mass of solvent = 200 g
Putting values in equation 1, we get:
Hence, the molar mass of solute is 115 g/mol.
Answer:
D
Explanation:
According to this question, each model of molecules in the options contains spheres of different colors and sizes representing different types of atoms. The atoms of the same element are the spheres of same color and size while atoms of different element are of different color or size.
Therefore, the model showing a molecule of a substance that is made up of three elements is model D because it is made up of three distinct spheres representing atoms of each element.
- The red sphere is the atom of the first element
- The big dark sphere is the atom of the second element
- The small white sphere is the atom of the third element
Answer:
The amount of isopropyl alcohol contained in 150 ml of the solution is 117.15 grams
Explanation:
The density of a substance is the mass per unit volume, therefore, we have;
The density of the isopropyl alcohol = 0.785 g/ml at 25°C
The density = mass/volume
Mass = Density × Volume
The mass of the 150 ml of isopropyl alcohol is therefore;
Mass = 0.785 g/ml × 150 ml = 117.15 g
The amount in grams contained in 150 ml of sample = 117.15 g.
Hey there!:
Volume of rainfall = Area X height
Height = 1 in = 0.254 dm
1mile2 = 2.59 X 10⁸ dm²
so 1300 miles² = 3367 *10⁸ dm²
Volume = 0.254 * 3367 * 10⁸ = 855.218 * 10⁸ dm³
Also,
H2SO4 ionizes as :
H2SO4 --> H⁺ + HSO4⁻
Ka1 is very high so it completely dissociates , due to first dissociation [H⁺] = Concentration of H2SO4
HSO4⁻ --> H⁺ + SO₄⁻²
We also consider it as high dissociation :
so each mole of H2SO4 will give 2 moles of H⁺ (proton)
pH = 3.30 = -log[H⁺]
So [H+] = 0.000501 M = 0.000501 moles / L or moles / dm³
Volume = 855.218 * 10⁸dm³
so moles of H+ present in this volume:
= 0.000501 * 855.218 *10⁸ = 4.28* 10⁷moles
So moles of H2SO4 = 4.28 * 10⁷ / 2 = 2.14 * 10⁷ moles
Molecular weight of H2SO4 = 98 g / mol
Mass of H2SO4:
Moles X molecular weight = 98 * 2.14 X 10⁷ grams = 209.72 * 10⁷ grams in kg:
= 2.09 X 10⁶Kg
Hope that helps!
