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andre [41]
3 years ago
11

Antimony has 2 naturally occurring isotopes. The mass of antimony-121 is 120.904 amu and the mass of antimony-123 is 122.904 amu

. Using the average atomic mass from the periodic table, find the abundance of each isotope. (Remember that the sum of the two abundances must be 100. Show your work.)
Chemistry
1 answer:
Sav [38]3 years ago
6 0
Wow, now this one is a hard one, took me quite a while to figure it out but here it is:
120.904(x)+122.904(1-x)=121.76 \\ 
120.904x-122.904x+122.904=121.76 \\ 
-2x+122.904=121.76 \\ 
-2x=-1.144 \\ 
x=.572  \\ 
1-.572=.428
The abundances of the two isotopes is:
Antimony-121 = 57.2%
Antimony-123 = 42.8%
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A client who weighs 70 kg is receiving a solution of 0.9% sodium chloride (normal saline) 500 ml with dopamine 800 mg at 5 ml/ho
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The mcg/kg/minute the client is receiving is 1.904 mcg/kg/min whose weight is 70 kg.

<h3>What does mcg kg mean?</h3>

1 milligram (mg) = 1000 micrograms (mcg) or 0.001 grams (g) 1 g = 1000 mg 1 kilogram (kg) = 1000 g 1 kg = 2.2 pound (lb) 1 liter (L) = 1000 milliliters (mL)

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