What is a sun spot? in the sun on the surface

1 answer:

5 0

Sunspots Are decreased temperature areas. So it might be bright all around the sun spots, and the dark spots are where the temperature is lower. They usually form in polar pairs, meaning that on the other side in the same spot there would be another sunspot

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Someone pls pls pls help me with this question.

Arisa [49]

$\rm{\pink{\underline{\underline{\blue{REASON:-}}}}}$

⭐ Elements in which the last electron enters any one of the five d-oribitals of their respective penultimate shells are called as d-block elements .

⭐ But the last electron of Zn , Cd , Hg and Cn enters in the s-oribital of their respective ultimate shells rather than the d-oribitals of their respective penultimate shells . Therefore, these elements cannot be regarded as d-block elements .

☃️ But properties of these elements resemble to the d-block elements rather than s-block elements .

☃️ Therefore, to make the study of periodic classification of elements more rational, they are studied along with d-block elements .

✍️ Thus on the basis of properties all transition elements are d- block elements, but on the basis of electronic configuration all d -block elements are not transition elements .

3 0

3 years ago

Find ΔHrxn for the following reaction: 2PbS(s)+3O2(g)→2PbO(s)+2SO2(g)

ch4aika [34]

Answer:

ΔH°rxn = -827.5 kJ

Explanation:

Let's consider the following balanced equation.

2 PbS(s) + 3 O₂(g) → 2 PbO(s) + 2 SO₂(g)

We can calculate the standard enthalpy of reaction (ΔH°rxn) from the standard enthalpies of formation (ΔH°f) using the following expression.

ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g) )] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g) )]

ΔH°rxn = [2 mol × (-217.32 kJ/mol) + 2 mol × (-296.83)] - [2 mol × (-100.4) + 3 mol × 0 kJ/mol]

ΔH°rxn = -827.5 kJ

5 0

3 years ago

An 80g sample of 3 1 H decays, leaving 2.5g of 3 1 H.

RUDIKE [14]

Here is the link to the answer:

7 0

2 years ago

Sylvanite is a mineral that contains 28.0% gold by mass. How much sylvanite would you need to dig up to obtain 73.0 g of gold?

Scorpion4ik [409]

You would have to dig up 261 g of sylvanite.

Mass of sylvanite = 73.0 g Au × (100 g sylvanite/28.0 g Au) = 261 g sylvanite.

3 0

3 years ago

1500 millimeters to km

gizmo_the_mogwai [7]

0.0015 kilometers is for sure the answer!

4 0

3 years ago