Answer:
hydrgen = i think it is 4
oxygen = i think it is 3
Explanation:
Answer:
15.98 L
Explanation:
First, you need to find T1, T2, V1 and V2.
T1 = 25 C = 298.15 K (25C + 273.15K)
T2 = 100 C = 373.15 K (100C + 273.15K)
V1 = 20. L
V2 = ? (we are trying to find)
Next, rearrange to fit the formula
V2 = V1 x T1 / T2
Next, fill in with our numbers
V2 = 20. L x 298.15 K / 373.15 K
Do the math and you should get...
15.98 L
- If you need more help or futher explanation please let me know. I would be glad to help!
The oxidation number of iodine is 5 in Mg(IO3)2 which can be calculated as
Mg(IO3)2
MgI2O6
As we know that
Mg has +2
O has -2
So,
(+2) + 2I + 6 (-2)=0
2 + 2I - 12 =0
10+ 2I =0
10 = 2I
I =5
Answer:
2.64 × 10⁶ g
Explanation:
We can find the mass of air using the ideal gas equation.
where,
P is the pressure (P = 1.00 atm)
V is the volume (V = 2.95 × 10⁶ L)
n is the number of moles
R is the ideal gas constant (0.08206atm.L/mol.K)
T is the absolute temperature (121°C + 273 = 394 K)
m is the mass
M is the molar mass (28.09 g/mol)
Answer:
The pH is 4.76
Explanation:
Step 1: Data given
Volume of a 0.476 M hydrocyanic acid solution = 29.8 mL = 0.0298 L
Volume of 0.487 M barium hydroxide solution = ?
Ka HCN = 6.2 * 10^-10
Step 2: Calculate pH
Hydrocyanic acid is a weak acid.
Barium hydroxide is a strong base.
The question asked = the pH BEFORE any base has been added, so we can ignore the base.
To calculate the pH of aweak acid, we need the pKa
HCN ⇔ H+ + CN-
Ka = [H+][CN-]/[HCN]
⇒ for weak acid: [H+]=[CN-]
Ka = [H+]²/[HCN]
[H+]² = [HCN]*Ka
[H+] = √([HCN]*Ka)
pH = -log(√([HCN]*Ka))
pH = -log(√(0.476 * 6.2*10^-10))
pH = 4.76
The pH is 4.76
