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2 years ago

How is volume and temperature related?

1 answer:

5 0

Charles' Law: The Temperature-Volume Law. This law states that the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature. As the volume goes up, the temperature also goes up, and vice-versa.

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What is important when it comes to winning

Dmitry_Shevchenko [17]

Answer:

satisfaction, enjoyment and fair play

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2 years ago

Read 2 more answers

What is the magnitude of velocity for a 2,000 kg car possessing 3,000 kg(*)m/s of momentum?

Trava [24]

The magnitude of velocity for this car is equal to 1.5 m/s.

<u>Given the following data:</u>

Momentum of car = 3,000 kgm/s.

Mass of car = 2,000 kg.

To calculate the magnitude of velocity for this car:

<h3>What is momentum?</h3>

In Science, momentum simply means a multiplication of the mass of an object and its velocity.

Mathematically, momentum is giving by the formula;

$Momentum = mass \times velocity$

Making velocity the subject of formula, we have:

$Velocity=\frac{Momentum}{Mass}$

Substituting the given parameters into the formula, we have;

$Velocity=\frac{3000}{2000}$

Velocity = 1.5 m/s.

Read more on momentum here: brainly.com/question/15517471

5 0

2 years ago

When you see yourself in a plane mirror, the image is always:

Charra [1.4K]

It’s c “ the same size as you are”

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2 years ago

An electron in the beam of a cathod-ray tube is accelerated by a potential difference of 2.12 kV . Then it passes through a regi

son4ous [18]

Answer:

B=9.1397*10^-4 Tesla

Explanation:

To find the velocity first we put kinetic energy og electron is equal to potential energy of electron

K.E=P.E

$\frac{1}{2}*m*v^{2} =e*V$

where :

m is the mass of electron

v is the velocity

V is the potential difference

$v=\sqrt{\frac{2*e*V}{m} }$ eq 1

Radius of electron moving in magnetic field is given by:

$R=\frac{m*v}{q*B}$ eq 2

where:

m is the mass of electron

v is the velocity

q=e=charge of electron

B is the magnitude of magnetic field

Put v from eq 1 into eq 2

$R=\frac{m*\sqrt{\frac{2*e*V}{m} } }{e B}$

$B=\sqrt{\frac{2*m*V}{e*R^{2} } }$

$B=\sqrt{\frac{2*(9.31*10^{-31})*(2.12*10^{3}) }{(1.60*10^{-19})*(0.170)^{2} } }$

B=9.1397*10^-4 Tesla

3 0

2 years ago

An important consideration in materials physics is the number of defects that are unavoidable due to statistical considerations.

goblinko [34]

Answer:

Explanation:

find attached the solution

8 0

2 years ago