Given:-
Mass of boulder = 10kg
Final Velocity = 15m/s
Acceleration due to gravity = +10m/s
To Find:-
The kinetic energy of the boulder as it lands
The potential energy of the boulder when it was at the top of the cliff
The height of the cliff
Formulae used:-
Kinetic energy = mv²/2
Potential energy = mgh
Now,
We will first find the Kinetic enrgy,
→ K. E = ½mv²
→ K. E = ½ × 10 × (15)²
→ K. E = 5 × 225
→ K. E =1125J
But we know that when the body starts moving the Potential enrgy of the body starts Converting into Kinetic enrgy. Before reaching to the last spot it has equal kinetic energy and Potential energy.
Therefore,
→ mgh = 1125J
The Potential enrgy of the boulder when it was on top is 1125J
Now,
→ mgh = 1125J
→ 10 × 10 × h = 1125J
→ 100h = 1125J
→ h = 1125/100
→ h = 11.25m
Hence, The Height of the Cliff is 11.25m
Thanks!
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