Ask question

Ask question

All categories

2 years ago

14

The DeMarco hotel has 500 rooms available for sale. For Monday night the hotel’s occupancy is 60%. What is the number of rooms t

he hotel has available to sell for Monday night? 100 200 250 300

1 answer:

mylen [45]2 years ago

6 0

Answer:

200 rooms are available to sell.

Step-by-step explanation:

Given,

Total number of rooms for Monday night = 500,

Occupancy percentage for Monday night = 60%,

Thus, the remaining rooms available for Monday Night

= (100-60)% of total rooms

= 40% of 500

$=\frac{40\times 500}{100}$

$=\frac{20000}{100}$

= 200

Therefore, there are 200 rooms available to sell for Monday night.

You might be interested in

What is the value of x when Rq=3x+2 ,QN =2x and SM=3x?

Andru [333]

The value of x is 2 because the centroid of the triangle divides each median in the ratio of 2:1 option (C) is correct.

<h3>What is the triangle?</h3>

The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

RQ = 3x+2 ,QN = 2x and SM=3x

In the figure, the TM, Rn, and SL are medians of the triangle SRT and Q is the centroid.

The centroid of the triangle divides each median in the ratio 2:1

RQ/QN = 2/1

(3x+2)/2x = 2/1

After solving:

3x + 2 = 4x

x = 2

Thus, the value of x is 2 because the centroid of the triangle divides each median in the ratio of 2:1 option (C) is correct.

Learn more about the triangle here:

brainly.com/question/25813512

#SPJ1

5 0

1 year ago

Three more than a certain number is 12 less than four times a number

k0ka [10]

Answer1.7 Step-by-ste explipcación:

4 0

2 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

$-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)$

$-\text{cos} \left(\theta\right)$

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

$\text{sec}(-\theta)=\text{sec}(\theta)$

And, $\text{sec}(\theta)=-0.73$

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0

2 years ago

Solve the equation -5x + 3 = 2x - 1

frozen [14]

Step-by-step explanation:

Given

- 5x + 3 = 2x - 1

or, 2x + 5x = 3 + 1

or, 6x = 4

or, x = 4/ 6

Therefore x = 2 /3

Hope it will help :)❤

8 0

2 years ago

Read 2 more answers

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

3 years ago