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hodyreva [135]
3 years ago
14

The triple point of a substance is the temperature and pressure conditions at which Select one: a. density is greatest. b. state

s of a substance coexist at equilibrium. c. equilibrium cannot occur. d. kinetic energy is at a minimum.
Chemistry
1 answer:
N76 [4]3 years ago
3 0

Answer:

Option b.

The triple point of a substance is the temperature and pressure conditions at which states of a substance coexist at equilibrium

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Which of the following would be produced when two or more different atoms bond chemically?
ExtremeBDS [4]

Answer:

When two or more atoms chemically bond with each other, the resultant chemical structure is a molecule. The familiar water molecule, H2O, consists of two hydrogen atoms and one oxygen atom; these bond together to form water,  irdk but it's either C or D

Explanation:

hope this helps have a good rest of your day :) ❤

7 0
3 years ago
Consider the reaction below.
saw5 [17]

This answer to this question is a rule that is applied to any reaction taken at dynamic equilibrium, with respect to 500 K. In other words, you can say that this reaction is of no use to us -

In a chemical equilibrium, it is known that the forward and reverse reactions occur at equal rates. At this point the concentrations of products and reactants remain constant, or in other words do not change

<u><em>Solution = Option C</em></u>

6 0
3 years ago
(20 points) i) An absorption intensity of 1.00 (in arbitrary units) is observed for the maximum peak of the 1:2:1 triplet of the
laiz [17]

Answer:

Concentration of ethanol required =  48.476 M

Explanation:

Given that:

the absorption intensity = 1.00

Molarity of ethanol = 1M

NMR instrument used = 160 MHz

Temperature used = 300 K

The required concentration of ethanol can be determined as follows:

=  ( 1 \ M \times \dfrac{160\ MHz }{450 \ MHz}) \times \dfrac{300 \ K}{2.2\ K}

=  ( 1 \ M \times 0.3555 ) \times136.36}

= 48.476 M

5 0
3 years ago
Assuming 100% dissociation, calculate the freezing point and boiling point of 1.22 m SnCl₄(aq). Constants may be found here.
Gekata [30.6K]

Answer:

T° freezing solution → -11.3°C

T° boiling solution → 103.1 °C

Explanation:

Assuming 100 % dissociation, we must find the i, Van't Hoff factor which means "the ions that are dissolved in solution"

This salt dissociates as this:

SnCl₄ (aq)  →   1Sn⁴⁺ (aq)  +   4Cl⁻  (aq)   (so i =5)

The formula for the colligative property of freezing point depression and boiling point elevation are:

ΔT = Kf . m . i

where ΔT = T° freezing pure solvent - T° freezing solution

ΔT = Kb . m . i

where ΔT = T° boiling solution - T° boiling pure solvent

Freezing point depression:

0° - T° freezing solution = 1.86°C/m . 1.22 m . 5

T° freezing solution = - (1.86°C/m . 1.22 m . 5) → -11.3°C

Boiling point elevation:

T° boiling solution - 100°C = 0.512 °C/m . 1.22 m . 5

T° boiling solution = (0.512 °C/m . 1.22 m . 5) + 100°C → 103.1 °C

8 0
3 years ago
Which formula represents lead (ii) phosphate? 1. pbpo4 2. pb4po4 3. pb3(po4)2 4. pb2(po4)3?
IrinaVladis [17]
3.) Charge on one molecule of PO4 is -3. So on two molecule it'll be 2(-3) = -6. Let oxidation number of Pb be x. Therefore, 3x+(-6) = 0. 3x=6. x=2.
6 0
3 years ago
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