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vampirchik [111]
3 years ago
9

1.

Physics
1 answer:
Valentin [98]3 years ago
7 0

Answer: F=\frac{3}{4} \frac{GM^{2}}{d^{2}}

Explanation:

According to Newton's law of Gravitation for the first case:

F_{o}=G\frac{(M)(M)}{d^2}=\frac{GM^2}{d^2}  (1)

Where:

F_{o} is the gravitational force

G is the Gravitational Constant

M is the mass of each container

d  is the distance between both containers

Now, for the second case the mass of the first container is 1.5 M and the second 0.5 M:

F=G\frac{(1.5 M)(0.5 M)}{d^{2}} (2)

Finally:

F=\frac{3}{4} \frac{GM^{2}}{d^{2}}

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JulsSmile [24]

Explanation:

V=u+at

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v=final speed

u=initial speed,(starting speed)

a=acceleration

t=time

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6=2+2a

2a=6-2

2a=4

a=4/2 = 2

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5.v=u+at

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A boy on board a cruise ship drops a 30. 0 gm marble into the ocean. If the resistive force proportionality constant is 0. 500 k
svlad2 [7]

The terminal speed of the marble is 0.588 m/s.

<h3>Calculation:</h3>

We know that,

F = mg                                                   ......(1)

where,

F = force

m = mass

g = acceleration due to gravity

Also,

v = F/k                                                       ......(2)

where,

v = terminal speed

k = proportionality constant

Substituting the value of F from equation (1) in equation (2)

v = mg/k                                                         .......(3)

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

To find,

v =?

Put the values in equation (3)

v = mg/k              

v = 0.03(9.8)/ 0.500

  = 0.294/0.500

  = 0.588 m/s

​

Hence, the terminal speed of the marble is 0.588 m/s.

Learn more about calculation of force here:

brainly.com/question/15562875

#SPJ4

.

5 0
2 years ago
Read 2 more answers
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