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vampirchik [111]
3 years ago
9

1.

Physics
1 answer:
Valentin [98]3 years ago
7 0

Answer: F=\frac{3}{4} \frac{GM^{2}}{d^{2}}

Explanation:

According to Newton's law of Gravitation for the first case:

F_{o}=G\frac{(M)(M)}{d^2}=\frac{GM^2}{d^2}  (1)

Where:

F_{o} is the gravitational force

G is the Gravitational Constant

M is the mass of each container

d  is the distance between both containers

Now, for the second case the mass of the first container is 1.5 M and the second 0.5 M:

F=G\frac{(1.5 M)(0.5 M)}{d^{2}} (2)

Finally:

F=\frac{3}{4} \frac{GM^{2}}{d^{2}}

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You shoot an arrow into the air. Two seconds later (2.00 s) the arrow has gone straight upward to a height of 35.0 m above its l
sdas [7]

This question can be solved by using the equations of motion.

a) The initial speed of the arrow is was "9.81 m/s".

b) It took the arrow "1.13 s" to reach a height of 17.5 m.

a)

We will use the second equation of motion to find out the initial speed of the arrow.

h= v_it + \frac{1}{2}gt^2\\

where,

vi = initial speed = ?

h = height = 35 m

t = time interval = 2 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

35\ m = (v_i)(2\ s)+\frac{1}{2}(9.81\ m/s^2)(2\ s)^2\\\\v_i(2\ s)=19.62\ m\\\\v_i = \frac{19.62\ m}{2\ s}

<u>vi =  9.81 m/s</u>

b)

To find the time taken by the arrow to reach 17.5 m, we will use the second equation of motion again.

h= v_it + \frac{1}{2}gt^2\\

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 17.5 m

vi = initial speed = 9.81 m/s

t = time = ?

Therefore,

17.5 = (9.81)t+\frac{1}{2}(9.81)t^2\\4.905t^2+9.81t-17.5=0

solving this quadratic equation using the quadratic formula, we get:

t = -3.13 s (OR) t = 1.13 s

Since time can not have a negative value.

Therefore,

<u>t = 1.13 s</u>

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

4 0
1 year ago
Sallys physical education teacher timed her run and recorded the time and distance in the table below. What is her average speed
Fudgin [204]
Answer: B) 2.5 m/s

Explanation: Find the average of the time and distance, and see how far they go in only 1 second.


1 + 2 + 3 + 4 + 5 = 15
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2 + 5 + 7 + 10 + 12 = 36
36 divided by 5 = 7.2


7.2m per 3 seconds.

7.2 divided by 3 = 2.4

Therefore, the answer is technically 2.4m/s
4 0
3 years ago
a wave is described by where x is in meters, y is in centimeters and t is in seconds. The angular frequency is
Sergeeva-Olga [200]

Complete Question

A wave is described by y(x,t) = 0.1 sin(3x + 10t), where x is in meters, y is in centimetres and t is in seconds. The angular wave  frequency is

Answer:

The  value is w =  10 \ rad /s

Explanation:

From the question we are told that  

    The equation describing the wave is y(x,t) = 0.1 sin(3x + 10t)

Generally the sinusoidal equation representing the motion of a wave is mathematically represented as

         y(x,t) =  Asin(kx + wt )

Where  w  is the  angular frequency

Now comparing this equation  with that given we see that

       w =  10 \ rad /s

 

               

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