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3 years ago

1.

Physics

1 answer:

Valentin [98]3 years ago

7 0

Answer: $F=\frac{3}{4} \frac{GM^{2}}{d^{2}}$

Explanation:

According to Newton's law of Gravitation for the first case:

$F_{o}=G\frac{(M)(M)}{d^2}=\frac{GM^2}{d^2}$ (1)

Where:

$F_{o}$ is the gravitational force

$G$ is the Gravitational Constant

$M$ is the mass of each container

$d$ is the distance between both containers

Now, for the second case the mass of the first container is $1.5 M$ and the second $0.5 M$ :

$F=G\frac{(1.5 M)(0.5 M)}{d^{2}}$ (2)

Finally:

$F=\frac{3}{4} \frac{GM^{2}}{d^{2}}$

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Answer:

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Part b)

Now if the voltage difference between the plates of capacitor is given constant

now the energy energy of capacitor is

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now when capacitance is changed to new value then new energy is given as

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Replacing in (1):

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Replacing in (1):

½ * v² + ½ (2/3 *m*r²) *(v/r)² = g*h

Replacing by the value given for h, and solving for v:

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Replacing in (1):

½ * v² + ½ (m*r²) *(v/r)² = g*h

Replacing by the value given for h, and solving for v:

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Replacing in (1):

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