Answer:
A. 1.19 * 10^(-13) N
B. 7.12 * 10^(15) m/s²
Explanation:
Parameters given:
Speed, v = 5.05 * 10^6 m/s
Angle, A = 64°
Magnetic field strength, B = 0.160T
Mass of proton, m = 1.673 * 10^(-27) kg
Charge of proton, q = 1.6023 * 10^(-19) C
A. Magnetic force is given as:
F = q*v*B*sinA
F = 1.6023 * 10^(-19) * 5.05 * 10^6 * 0.160 * sin64
F = 1.19 * 10^(-13) N
B. Force is generally given as:
F = m*a
Hence, we can find acceleration, a, by making it the subject of formula:
a = F/m
a = (1.19 * 10^(-13))/(1.673 * 10^-27)
a = 7.12 * 10^15 m/s²
Answer:
D
Explanation:
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Answer:
snow is 64.638 kg / hr
Explanation:
Given data
wide w = 21 feet
long L = 20 ft
area A = 1350 square foot
mass of snow m = 1.90 mg
to find out
snow in kilograms / hour
solution
we will find snow in kg
so we apply formula that is
snow kg / hour = w × L ×A × m × 60/10^6
put all value we get snow
snow = 21 × 20 × 1350 × 1.90 × 60/10^6
snow = 420 × 1350 × 1.90 × 60/10^6
snow = 1077300 × 60/10^6
snow = 64.638
hence snow is 64.638 kg / hr
Answer:
Change in specific internal Energy
Explanation:
Given:
- Mass of the gas, m=0.4 lb
- Initial pressure and volume are
- Final pressure and temperature are
- Heat transfer from the gas is 2.1 Btu
Since the process is isotropic we have
So the final volume of the gas is calculated.
Work in any isotropic is given by w
According to the first law of thermodynamics we have
So the Specific Internal Change is given by
So the specific Change in Internal energy is calculated.
