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andrezito [222]
3 years ago
11

How does the force of gravity affect the rate of acceleration?

Physics
1 answer:
Vesnalui [34]3 years ago
3 0
Gravity lets all objects fall to the ground at the same speed, 9.8 m/s/s. If the force of gravity were stronger, such as 10 m/s/s, the rate of acceleration would be faster.
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What is the law of conservation of energy?
geniusboy [140]

Answer:

The answer is A

7 0
3 years ago
The specific heat(c) of copper is 0.39 J/g °C. What is the temperature
horsena [70]

Answer:12.8°c

Explanation:

specific heat capacity of copper(c)=0.39J*g°c

Mass(m)=20grams

Quantity of heat(Q)=100joules

Temperature rise(@)=?

@=Q/(mxc)

@=100/(20x0.39)

@=100/7.8

@=12.8°c

8 0
4 years ago
During the time that the blocks are in contact, describe whether the center of mass of the two-block system is speeding up, slow
iVinArrow [24]

Answer:

The center of mass of the two-block system is staying the same and it can be explained with the help of linear momentum equation.

Explanation:

The center of mass of the two-block system is staying the same and it can be explained with the help of linear momentum equation.

Equation:

P=mv

This equation holds if no external force is acting on the system it means the momentum of the system is constant.

In our case, there is no external force which means the total momentum of system is constant:

P=constant

Total mass of system is also constant:

m=constant

It means the velocity of the system is constant (from above equation) thus center of mass of the two-block system is staying the same

3 0
3 years ago
Brainliest if correct
ozzi

Answer:

It's is c coz the weight is equal to the normal force

7 0
3 years ago
Determine the centripetal force upon a 40-kg child who makes 10 revolution around the cliffhanger in 29.3 seconds.the radius of
zysi [14]

Answer:

The centripetal force acting on the child is 39400.56 N.

Explanation:

Given:

Mass of the child is, m=40\ kg

Radius of the barrel is, R=2.90\ m

Number of revolutions are, n =10

Time taken for 10 revolutions is, t=29.3\ s

Therefore, the time period of the child is given as:

T=\frac{n}{t}=\frac{10}{29.3}=0.341\ s

Now, angular velocity is related to time period as:

\omega=\frac{2\pi}{T}=\frac{2\pi}{0.341}=18.43\ rad/s

Now, centripetal force acting on the child is given as:

F_{c}=m\omega^2 R\\F_{c}=40\times (18.43)^2\times 2.90\\F_{c}=40\times 339.66\times 2.90\\F_{c}=39400.56\ N

Therefore, the centripetal force acting on the child is 39400.56 N.

8 0
3 years ago
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