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miskamm [114]
2 years ago
12

12. A frain moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?

Physics
1 answer:
ziro4ka [17]2 years ago
6 0
  • initial velocity=u=0m/s
  • Final velocity=v=25m/s
  • Time=t=30s

\\ \tt\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \tt\longmapsto Acceleration=\dfrac{25-0}{30}

\\ \tt\longmapsto Acceleration=\dfrac{25}{30}

\\ \tt\longmapsto Acceleration=0.8m/s^2

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A force of 8800 N is exerted on a piston that has an area of 0.010 m^2. What is the force exerted by a second piston that has an
professor190 [17]

Explanation:

It is given that,

Force on piston, F₁ = 8800 N

Area, A_1=0.01\ m^2

Area, A_2=0.04\ m^2

Let F₂ is the force exerted on the second piston. Using Pascal's law as :

Pressure at piston 1 = Pressure at piston 2

\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}

F_2=\dfrac{F_1}{A_1}\times A_2

F_2=\dfrac{8800}{0.01}\times 0.04

F_2=35200\ N

So, the force exerted by a second piston is 35200 N. Hence, this is the required solution.

8 0
3 years ago
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Question 1
kakasveta [241]

Answer:

W = 600 J

Explanation:

We have,

According to attached figure,

Height of the inclined plane is 60 m

Force acting on the block is 10 N

It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :

W = mgh

or

W=F\times h\\\\W=10\times 60\\\\W=600\ J

So, the work done against the gravity is 600 J.

3 0
3 years ago
A solid uniformly charged insulating sphere has uniform volume charge density p and radius R. Apply Gauss's law to determine an
RUDIKE [14]

Answer:

electric field E = (1 /3 e₀) ρ r

Explanation:

For the application of the law of Gauss we must build a surface with a simple symmetry, in this case we build a spherical surface within the charged sphere and analyze the amount of charge by this surface.

The charge within our surface is

 

     ρ = Q / V

     Q ’= ρ V '

The volume of the sphere is V = 4/3 π r³

     Q ’= ρ 4/3 π r³

The symmetry of the sphere gives us which field is perpendicular to the surface, so the integral is reduced to the value of the electric field by the area

      I E da = Q ’/ ε₀

      E A = E 4 πi r² = Q ’/ ε₀

      E = (1/4 π ε₀) Q ’/ r²

Now you relate the fraction of load Q ’with the total load, for this we use that the density is constant

     

      R = Q ’/ V’ = Q / V

How you want the solution depending on the density (ρ) and the inner radius  (r)

      Q ’= R V’

      Q ’= ρ 4/3 π r³

      E = (1 /4π ε₀) (1 /r²) ρ 4/3 π r³

     E = (1 /3 e₀) ρ r

4 0
3 years ago
According to the law of universal gravitation, any two objects are attracted to each other. The strength of the gravitational fo
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C. Planet A orbits its star faster than Planet B.

Explanation:

since Planet A is closer to the star due to its gravitational force, it will orbit its star faster than planet B

hope this helps :)

5 0
2 years ago
What element shares the property of forming ions with a 1+ charge?
Oduvanchick [21]

Answer:

the Group 1A metals such as sodium and potassium form +1 charges,

Explanation:

5 0
3 years ago
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