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Svet_ta [14]
3 years ago
12

Can someone show me a step by step with the answer?

Chemistry
1 answer:
Georgia [21]3 years ago
8 0

Answer:

6 mols HCl

Explanation:

(I'm an AP chemistry student but not perfect at this stuff)

you can use the Molarity=Moles/L equation here:

(6M)=(moles HCl)/(1L)

divide by 1 on both sides to isolate the moles of HCl

this gets you 6 moles HCl.

Again I'm just a student so my answer might be wrong, but this question should just require the M=mols/L equation :).

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2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

4 0
3 years ago
Which organism is the carnivore in this food web?
mihalych1998 [28]
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8 0
3 years ago
At which temperature will the least amount of time pass before someone detects the odor of a fragrant flower?
alukav5142 [94]
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7 0
4 years ago
Please answer all of the questions
anzhelika [568]

Here's your ans

Explanation:

1-1.50

2-d

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Tq

3 0
3 years ago
What is the empirical formula of a compound containing 40.0% sulfur and 60.0% oxygen by mass?
gizmo_the_mogwai [7]

in order to determine empirical formula we have to determine the mole ratio of the given elements

Let the total mass of the compound is 100g

as given that the compound has 40% sulfur , so mass of sulfur = 40g

as given that the compound has 60% oxygen, so mass of oxygen = 60g

let us calculate the moles of each element

Moles of sulfur = mass / atomic mass = 40 / 32 = 1.25

moles of oxygen = mass / atomic mass = 60/ 16 = 3.75

In order to get simple ratio of moles we will divide both the moles with least number of moles which is 1.25

moles of sulfur = 1.25 / 1.25 = 1

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So empirical formula will be SO₃

3 0
3 years ago
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