Answer:
Distance, d = 61.13 ft
Explanation:
It is given that,
Initial speed of the car, u = 50 mi/h = 73.34 ft/s
Finally, it stops i.e. v = 0
Deceleration of the car, 
We need to find the distance covered before the car comes to a stop. Let the distance is s. It can be calculated using third law of motion as :
s = 61.13 ft
So, the distance covered by the car before it comes to rest is 61.13 ft. Hence, this is the required solution.
The box is accelerated from rest to 4 m/s in a matter of 2.5 s, so its acceleration <em>a</em> is such that
4 m/s = <em>a</em> (2.5 s) → <em>a</em> = (4 m/s) / (2.5 s) = 1.6 m/s²
Then the force applied to the box has a magnitude <em>F</em> such that
<em>F</em> = (10 kg) (1.6 m/s²) = 16 N
Answer:
The Answer is B because the material the object is made of, the position, or the color have absolutely nothing to do with gravitational potential energy
Answer: There is no change in temperature when heat is given out or taken in by the object
Explanation:
The heat capacity of an object is infinite when it undergoing phase transition since the heat is ued in changing the state of the substance and ntot in raising the teperature of the substiance. Thus, heat capacity is infinite during change of state. This is known as latent heat. The correct option is
There is no change in temperature when heat is given out or taken in by the object
Answer:
ANGLE is 35.3 degree celcius
Explanation:
Given data:
mass m and 3m
initial speed Vi
particle with mass m is moving toward left while particle with mass 3m is moving toward right
By using conservation of momentum :
conservation of energy :
After collision, particle with mass m moves at right angles, thus by considering conservation of momentum in x & y direction,
x direction : 
y direction : 
subsitute these value in energy conservation
35.3 degree from x-axis
