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Tju [1.3M]
4 years ago
8

The amount of of space an object occupies, 6 letter word

Chemistry
1 answer:
Marina CMI [18]4 years ago
6 0
6 letter word for the amount of space an object occupies would be volume.
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12.Calculate the wavelength of an object moving with a velocity of 5 x105 m s-1
uranmaximum [27]

Answer:

Wavelength, \lambda=3.3\times 10^{-18}\ m

Explanation:

We have,

Velocity of the object, v=5\times 10^5\ m/s

Mass of the object, m=4\times 10^{-22}\ kg

It is required to find the wavelength of the object. The relation between wavelength and velocity of the object is given by :

\lambda=\dfrac{h}{mv}

h is Planck's constant

\lambda=\dfrac{6.6\times 10^{-34}}{4\times 10^{-22}\times 5\times 10^5}\\\\\lambda=3.3\times 10^{-18}\ m

So, the wavelength of the object is 3.3\times 10^{-18}\ m.      

5 0
4 years ago
How much silver can be produced from 125g of Ag2S
rosijanka [135]

Answer:

108.9g of Silver can be produced from 125g of Ag2S

Explanation:

The compound Ag2S shows that two atoms of Silver Ag, combined with an atom of Sulphur S to form Ag2S. We can as well say the combination ration of Silver to Sulphur is 2:1

•Now we need to calculate the molecular weight of this compound by summing up the molar masses of each element in the compound.

•Molar mass of Silver Ag= 107.9g/mol

•Molar mass of Sulphur S= 32g/mol

•Molecular weight of Ag2S= (2×107.9g/mol) + 32g/mol

•Molecular weight of Ag2S= 215.8g/mol + 32g/mol= 247.8g/mol

•From our calculations, we know that 215.8g/mol of Ag is present in 247.8g/mol of Ag2S

If 247.8g Ag2S produced 215.8g Ag

125g Ag2S will produce xg Ag

cross multiplying we have

xg= 215.8g × 125g / 247.8g

xg= 26975g/247.8

xg= 108.85g

Therefore, 108.9g of Silver can be produced from 125g of Ag2S

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3 years ago
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