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Nikolay [14]
3 years ago
6

Question 4 Calculate the nlass of 7.1 x 1024 formula units of magnesium hydroxide, Mg(OH),.

Chemistry
1 answer:
faust18 [17]3 years ago
6 0

its me again this is how you find the answer. note: i dont have the periodic table to see the exact atomic mass to find the molar mass however this is the answer:

so the actual formula is Mg(OH) with a 2 as a subscript because there are 2 Mg. so with Mg(OH)2 the Molar mass is 58.32g/mol. 58.32 g/mol x 7.1x1024 = 4.1x1026g

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Determine the empirical formula for c6n4o10
ANEK [815]
<h2>Let us derive empirical formula </h2>

Explanation:

We are given with compound C₆N₄O₁₀: mass percentage of all is :

For C = 12 x 6 /288=0.25%

For N= 14 x 4 /288=0.19%

For 0= 16 x 10/288=0.5%

The elements present are :

         Atomic mass   moles                       Simplest ratio           rounding off

C      12                        0.25/12=0.020             0.02/0.02=1           2

N       14                       0.9/14=0.06                    0.06/0.02=3         6

O       16                        0.5/16=0.03                   0.03/0.02=1.5       3

The empirical formula derived is : C₂n₆O₃

7 0
3 years ago
Which liquid has the highest vapor pressure
Harlamova29_29 [7]
Propanone is the liquid with the high vapor pressure. At standard of 101.3 kPa, it has the temperature of 50 degrees Celsius.
4 0
3 years ago
Check wether all the answers are correct or not. please?​
zhenek [66]

Answer:

I dont now but I think it is correct

3 0
3 years ago
Read 2 more answers
luminum and oxygen react according to the following equation: 4Al(s) +3O2(g) --&gt; 2Al2O3(s) What mass of Al2O3, in grams, can
Slav-nsk [51]

Answer: 8.7 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.  

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{4.6g}{27g/mol}=0.17moles

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

As oxygen is in excess, Aluminium is the limiting reagent and limits the formation of products.

According to stoichiometry:

4 moles of aluminium give = 2 moles of Al_2O_3(s)

Thus 0.17 moles of aluminium give=\frac{2}{4}\times 0.17=0.085mol

Mass of Al_2O_3=moles\times {\text {molar mass}}=0.085\times 102g/mol=8.7g

Thus the mass of Al_2O_3(s)  is 8.7 grams

8 0
3 years ago
Determine which of the following pairs of reactants will result in a spontaneous reaction at 25°C. None of the above pairs will
Alla [95]

Answer:

Only Fe^{3+}+Mg gives spontaneous reaction.

Explanation:

A redox reaction will be spontaneous if standard reduction potential (E^{0}) of the reaction is positive. Because it leads to negative standard gibbs free energy change (\Delta G^{0}), which is a thermodynamic condition for spontaneity of a reaction.

E^{0}=E^{0}(reduction)-E^{0}(oxidation)

Where E^{0}(reduction) and E^{0}(oxidation) represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.

(1) Oxidation:         Mg-2e^{-}\rightarrow Mg^{2+} ;  E_{Mg^{2+}\mid Mg}^{0}=-2.38V

Reduction:         Fe^{3+}+3e^{-}\rightarrow Fe ; E_{Fe^{3+}\mid Fe}^{0}=-0.04V

So, E^{0}=E_{Fe^{3+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}=(-0.04+2.38)V=2.34V

Hence this pair will give spontaneous reaction.

(2) Similarly as above, E^{0}=E_{Pb^{2+}\mid Pb}^{0}-E_{Au^{+}\mid Au}^{0}=(-0.13-1.69)V=-1.82 V

Hence this pair will give non-spontaneous reaction.

(3) Similarly as above, E^{0}=E_{Ag^{+}\mid Ag}^{0}-E_{Br_{2}\mid Br^{-}}^{0}=(0.80-1.07)V=-0.27 V

Hence this pair will give non-spontaneous reaction.

(4)  Similarly as above, E^{0}=E_{Li^{+}\mid Li}^{0}-E_{Cr^{3+}\mid Cr}^{0}=(-3.04+0.74)V=-2.30 V

Hence this pair will give non-spontaneous reaction.

6 0
3 years ago
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