<h2>Let us derive empirical formula </h2>
Explanation:
We are given with compound C₆N₄O₁₀: mass percentage of all is :
For C = 12 x 6 /288=0.25%
For N= 14 x 4 /288=0.19%
For 0= 16 x 10/288=0.5%
The elements present are :
Atomic mass moles Simplest ratio rounding off
C 12 0.25/12=0.020 0.02/0.02=1 2
N 14 0.9/14=0.06 0.06/0.02=3 6
O 16 0.5/16=0.03 0.03/0.02=1.5 3
The empirical formula derived is : C₂n₆O₃
Propanone is the liquid with the high vapor pressure. At standard of 101.3 kPa, it has the temperature of 50 degrees Celsius.
Answer:
I dont now but I think it is correct
Answer: 8.7 grams
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
of particles.
To calculate the moles, we use the equation:


As oxygen is in excess, Aluminium is the limiting reagent and limits the formation of products.
According to stoichiometry:
4 moles of aluminium give = 2 moles of 
Thus 0.17 moles of aluminium give=
Mass of 
Thus the mass of
is 8.7 grams
Answer:
Only
gives spontaneous reaction.
Explanation:
A redox reaction will be spontaneous if standard reduction potential (
) of the reaction is positive. Because it leads to negative standard gibbs free energy change (
), which is a thermodynamic condition for spontaneity of a reaction.

Where
and
represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.
(1) Oxidation:
; 
Reduction:
; 
So, 
Hence this pair will give spontaneous reaction.
(2) Similarly as above, 
Hence this pair will give non-spontaneous reaction.
(3) Similarly as above, 
Hence this pair will give non-spontaneous reaction.
(4) Similarly as above, 
Hence this pair will give non-spontaneous reaction.