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Paha777 [63]
3 years ago
13

Why our body is not crushed due to atmostsparic pressure​

Chemistry
1 answer:
kirill [66]3 years ago
7 0
Fluid and air flows around you and tries to crush you in but Fortunately, there is typically just as much pressure inside your body pressing outward as there is air pressure outside your body pushing inward. They typically cancel out, meaning that there is no overall force on you and you don't get crushed.
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The atomic mass of Gallium is 69.72 AMU. The masses of the naturally occurring isotopes are 68.9257 AMU and 70.908 AMU for Ga-69
Mashcka [7]

Answer:

40.7% abundance of Ga-71

59.93% abundance of  Ga-69

Explanation:

Given data:

Average atomic mass of Ga = 69.72 amu

Atomic mass of Ga-69 = 68.9257 amu

Atomic mass of Ga-71 = 70.908 amu

Percent abundance of each isotope = ?

Solution;

we know there are two naturally occurring isotopes of Ga.

First of all we will set the fraction for both isotopes

X for the isotopes having mass 68.9257

1-x for isotopes having mass 70.908

we will use the following equation,

68.9257x +  70.908 (1-x) = 69.72

68.9257x +70.908 - 70.908x = 69.72

68.9257x -  70.908x = 69.72 - 70.908

-1.9823x =  - 1.188

x=  1.188/1.9823

x= 0.5993

0.5993 × 100 = 59.93 %

59.93 %  is abundance of Ga-69 because we solve the fraction x.

now we will calculate the abundance of Ga-71.

(1-x)

1 - 0.5993 = 0.4007

0.4007× 100= 40.7 %

40.7 % for Ga-71.

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What is Δn for the following equation in relating Kc to Kp?2 SO2(g) + O2(g) ↔ 2 SO3(g)23-2-11
san4es73 [151]

Answer:

-1

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2SO_2_{(g)}+O_2_{(g)}\rightleftharpoons2SO_3_{(g)}

<u>Δn = (2)-(2+1) = -1  </u>

Thus, Kp is:

K_p=  K_c\times (RT)^{-1}

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