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2 years ago

Which of the following terms is a term that could refer to heterogeneous matter? a. element b. mixture c. compound d. solution

Chemistry

1 answer:

kupik [55]2 years ago

6 0

Answer : b. mixture

<h3>Further explanation</h3>

Element and compound are included in pure substance where the composition is the same in each part

Elements are made up of 1 type of atom, while the compounds of 2 or more types of atoms , both can be represented in the form of chemical symbols

A mixture is a combination of substances. The properties of a substance in the mixture component are unchanged

The mixture can be a homogeneous mixture or a heterogeneous mixture

the homogeneous mixture if each part has the same composition

the heterogeneous mixture if each part has a different composition

Solution including into Homogeneous mixture, while suspension into a heterogeneous mixture

So a term that could refer to heterogeneous matter : b. mixture

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24-Complete the following sentence:

docker41 [41]

Answer:

B. Solvent

Explanation:

In osmosis, water always moves from low solute concentration to high solute concentration. SOLUTE NEVER MOVES AS IT CANNOT PASS THE SELECTIVELY PERMEABLE MEMBRANE. alot of caps but need to stress this concept cuz otherwise this concept gets very confusing

8 0

2 years ago

Consider 100.0 g samples of two different compounds consisting only of carbon and oxygen. One compound contains 27.2 g of carbon

Pani-rosa [81]

Answer: The ratio of carbon in both the compounds is 1 : 2

Explanation:

Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a given mass of the other element are present in the ratios of small whole number. For Example: $Cu_2O\text{ and }CuO$

For Sample 1:

Total mass of sample = 100 g

Mass of carbon = 27.2 g

Mass of oxygen = (100 - 27.7) = 72.8 g

To formulate the formula of the compound, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{27.2g}{12g/mole}=2.26moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{72.8g}{16g/mole}=4.55moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.26 moles.

For Carbon = $\frac{2.26}{2.26}=1$

For Oxygen = $\frac{4.55}{2.26}=2.01\approx 2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 2

Hence, the formula for sample 1 is $CO_2$

For Sample 2:

Total mass of sample = 100 g

Mass of carbon = 42.9 g

Mass of oxygen = (100 - 42.9) = 57.1 g

To formulate the formula of the compound, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.9g}{12g/mole}=3.57moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{57.1g}{16g/mole}=3.57moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.57 moles.

For Carbon = $\frac{3.57}{3.57}=1$

For Oxygen = $\frac{3.57}{3.57}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 1

Hence, the formula for sample 1 is $CO$

In the given samples, we need to fix the ratio of oxygen atoms.

So, in sample one, the atom ratio of oxygen and carbon is 2 : 1.

Thus, for 1 atom of oxygen, the atoms of carbon required will be = $\frac{1}{2}\times 1=\frac{1}{2}$

Now, taking the ratio of carbon atoms in both the samples, we get:

$C_1:C_2=\frac{1}{2}:1=1:2$

Hence, the ratio of carbon in both the compounds is 1 : 2

8 0

2 years ago

A compound with the empirical formula CH 2 O has a formula mass of 180 g/mol. What is its molecular formula

olga nikolaevna [1]

Empirical formula mass

12+2(1)+16
28+2
30g/mol

Molecular fornula mass:-180g/mol

n=Molecular formula mass/Empirical formula mass
m=180/30
n=6

Molecular formula:-

n×Empirical formula
6(CH_2O
C_6H_12 O_6

5 0

1 year ago

Brainliest if answered correctly How many Calcium (CA) atoms are in carbon tetrachloride

Lady_Fox [76]

Answer:

What atoms are present in carbon tetrachloride?

There is 1 carbon, and 4 chlorine atoms (or chloride ions if you want to get technical). Tetra means 4 in Greek.

hope that helps❤

4 0

2 years ago

Read 2 more answers

Calculate the mass of 1.9 • 10^24 atoms of Pb

Marrrta [24]

Answer:

65.4 is the mass for 1.9×10²⁴ atomsof Pb

Explanation:

1mol of atoms of Pb has → NA (6.02×10²³ atoms) and weighs → 207.2 g

Therefore 1.9×10²⁴ atomsof Pb may weigh (1.9×10²⁴ . 207.2) / NA = 65.4 g

7 0

2 years ago