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Anika [276]
3 years ago
13

Which of the following terms is a term that could refer to heterogeneous matter? a. element b. mixture c. compound d. solution

Chemistry
1 answer:
kupik [55]3 years ago
6 0

Answer : b. mixture

<h3>Further explanation</h3>

Element and compound are included in pure substance where the composition is the same in each part

Elements are made up of 1 type of atom, while the compounds of 2 or more types of atoms , both can be represented in the form of chemical symbols

A mixture is a combination of substances. The properties of a substance in the mixture component are unchanged

The mixture can be a homogeneous mixture or a heterogeneous mixture

  • the homogeneous mixture if each part has the same composition
  • the heterogeneous mixture if each part has a different composition

Solution including into Homogeneous mixture, while suspension into a heterogeneous mixture

So a term that could refer to heterogeneous matter : b. mixture

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Answer : The correct answer is 96.68 yrs

Radioactivity Decay :

it is a process in which a nucleus of unstable atom emit energy in form of radiations like alpha particle , beta particle etc .

Radioactive decay follows first order kinetics , so its rate , rate constant , amount o isotopes can be calculated using first order equations .

The first order equation for radioactive decay can be expressed as :

ln \frac{N}{N_0}  = - k*t ----------- equation (1)

Where : N = amount of radioisotope after time "t"

N₀ = Initial amount of radioisotope

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Following steps can be used to find time :

1) To find deacy constant :

Decay constant can be calculated using half life . Decay constant and half life can be related as :

T _\frac{1}{2} = \frac{ln2}{k} ---------equation (2)

Given : Half life of Strontium -90 = 28.8 years

Plugging value of T_\frac{1}{2} in above formula (equation 2) :

28.8 yrs = \frac{ln 2}{ k }

Multiply both side by k

28.8 yrs * k = \frac{ln 2 }{k} * k

Dividing both side by 28.8 yrs

\frac{28.8 yrs * k}{28.8 yrs} = \frac{ln 2}{28.8 yrs}

(ln 2 = 0.693 )

k = 0.0241 yrs⁻¹

Step 2 : To find time :

Given : N₀ = 10.3 ppm N = 1.0 ppm k = 0.0241 yrs⁻¹

Plugging these value in equation (1) as :

ln (\frac{1.0 ppm}{10.3 ppm} ) = - 0.0241 yrs^-^1 * t

ln (0.0971 ) = -0.0241 yrs ^-^1 * t

(ln 0.0971 = - 2.33 )

Dividing both side by - 0.0241 yrs⁻¹

\frac{-2.33}{-0.0241 yrs^-^1} = \frac{-0.0241 yrs^-^1 * t}{-0.0241 yrs^-^1}

t = 96.68 yrs

Hence the concentration of Strontium-90 will drop from 10.3 ppm to 1.0 ppm is 96.68 yrs

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Answer:

volume = 0.288 L

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<u>(Step 1)</u>

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Molar Mass (LiBr): 86.845 g/mol

100 grams LiBr           1 mole
-----------------------  x  ------------------  =  1.15 moles LiBr
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