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3 years ago

Which of the following terms is a term that could refer to heterogeneous matter? a. element b. mixture c. compound d. solution

Chemistry

1 answer:

kupik [55]3 years ago

6 0

Answer : b. mixture

<h3>Further explanation</h3>

Element and compound are included in pure substance where the composition is the same in each part

Elements are made up of 1 type of atom, while the compounds of 2 or more types of atoms , both can be represented in the form of chemical symbols

A mixture is a combination of substances. The properties of a substance in the mixture component are unchanged

The mixture can be a homogeneous mixture or a heterogeneous mixture

the homogeneous mixture if each part has the same composition

the heterogeneous mixture if each part has a different composition

Solution including into Homogeneous mixture, while suspension into a heterogeneous mixture

So a term that could refer to heterogeneous matter : b. mixture

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Darya [45]

Answer:

Q.89

Alkane - CnH(2n+2)

given that 8 H = > 8= 2n+2

therefore n= 3

C3H8 = 12×3 + 8×1= 36 +8 = 44

4 0

3 years ago

Which one is not acid? Na₂O or CO₂

vodka [1.7K]

Answer:

It is Na2O because it doesn't show any acidic properties.

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2 years ago

He balanced equation for the reaction of acetylene, c2h2, and oxygen in an acetylene torch is 2 c2h2 + 5 o2 → 4 co2 + 2 h2o. in

pickupchik [31]

Answer: 0.4 g

Explanation:

1) Balanced chemical equation:

2) 2C2H2 + 5 O2 → 4CO2 + 2 H2O

3) mole ratios:

2 mol C2h2 : 5 mol O2

4) Convert 0.13 g C2H2 into number of moles

n = mass in grams / molar mass

molar mass C2H2 = 2 *12g/mol + 2*1 g/mol = 26 g/mol

n = 0.13 g / 26 g/mol = 0.005 mol

5) Set the proportion with the unknown

5 mol O2 x
----------------- = ---------------
2 mol C2H2 0.005 mol C2H2

x = 0.005 mol C2H2 * 5 mol O2 / 2 mol C2H2 = 0.0125 mol O2

6) Convert 0.0125 mol O2 to grams

mass = number of moles * molar mass

molar mass of O2 = 32 g/mol

mass = 0.0125 mol * 32 g/mol = 0.4 g

Answer: 0.4 g

8 0

3 years ago

A balloon was partially filled with helium gas at room temperature. It occupied 4.0 liters of volume at 700.0 mmHg atmospheric p

Tatiana [17]

Answer:

28.28 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have two different values of V and P:

P₁V₁ = P₂V₂

P₁ = 700.0 mm Hg, V₁ = 4.0 L.

at burst: P₂ = 99.0 mm Hg, V₂ = ??? L.

∴ V₂ = P₁V₁/P₂ = (700.0 mm Hg)(4.0 L)/(99.0 mm Hg) = 28.28 L.

3 0

3 years ago

What is the mole ratio of PbO2 to water? PbO, H,0 = 1:0

ipn [44]

Answer:

The mole ratio of PbO2 to H2O is 1 : 2.

Explanation:

The balanced reaction equation is:

Pb + PbO2 + 2H2SO4 → 2PbSO4 + 2H2O

On the reactant side, we have 1 mole of Pb, 1 mole of PbO2, 2 moles of H2SO4.

On the product side, we have 2 moles of PbSO4 and 2 moles of H2O.

This means that for ever 1 mole of PbO2 consumed, 2 moles of water is formed as product.

Hence, the mole ratio of PbO2 to H2O is 1 : 2.

5 0

3 years ago