The purpose of the scapula to move during arm elevation is increase the range of elevation of the arm.
<h3>What is the importance of movement of the scapula during arm elevation?</h3>
The scapula is an important bone which is found in the shoulder and back region of the body.
The scapula enables and increases the range of motion of the arm with its motions.
During arm elevation, the scapula undergoes an upward rotational motion.
Therefore, the purpose of the scapula to move during arm elevation is increase the range of elevation of the arm.
Learn more about scapula motion at: brainly.com/question/5133017
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Answer:
1.3 × 10⁸ e⁻
Explanation:
When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:
20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻
1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:
2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻
Answer:
true?
Explanation:
Im positive but not 100% sure wait for someone else to answer and see if they say the same.
Answer:
19.2m/s
Explanation:
Assuming that 2.4m/s^2 was the acceleration and not a typo, we can use the equation v=at, where v=velocity, a=acceleration, and t=time,
plug in known varibles,
v=2.4*8
v=19.2m/s
