172 + 115 cos 31 +115 cos 48 horizontally
115 sin 31 - 115 sin 48 vertically
possibly need some drawing
The period of the pendulum is given by the following equation
T = 2<span>π * sqrt (L/g)
Where g is the gravity (free fall acceleration)
L is the longitude of the pendulum
T is the period.
We find g.............> (T /2</span>π)<span>^</span><span>2 = L/g
g = L/(</span>T /2π)^2...........> g = 22.657 m/s^2