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IceJOKER [234]
3 years ago
11

You decide to walk part of the way around a lake. The lake is a circle with a radius of 2.0 km You start on the shore due south

of the lake and walk three-fourths of the way around the lake. ending up on the shore due east of the lake. What is your displacement?
Physics
1 answer:
AveGali [126]3 years ago
7 0

Answer:

2.828 km

Explanation:

radius of lake, r = 2 km

Let O be the centre of the circular lake and you walk from A to A to D.

Displacement is the measure of shortest distance between two points.

According to the diagram , the displacement AD is

AD^{2}=AO^{2}+OD^{2} (By using the Pythagorean theorem)

AD^{2}=2^{2}+2^{2}

AD = 2.828 km

thus, the displacement is 2.828 km.

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What is the kinetic energy of a ball that has a mass of 3kg and Is<br> moving at 5m/s?
Arada [10]

Answer:

E kin = 1/2 • m • v^2

E kin: kinetic energy

m: mass

v: velocity

Explanation:

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A elephant kicks a 5.0\,\text {kg}5.0kg5, point, 0, start text, k, g, end text stone with 150\,\text J150J150, start text, J, en
S_A_V [24]

The speed of the stone is 7.7 m/s

Explanation:

The kinetic energy of a body is the energy possessed by the body due to its motion. Mathematically,

K=\frac{1}{2}mv^2

where

m is the mass of the body

v is its speed

For the stone in this problem, we have:

K = 150 J is its kinetic energy

m = 5.0 kg is its mass

Re-arranging the equation for v, we find the speed of the stone:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(150)}{5.0}}=7.7 m/s

Learn more about kinetic energy:

brainly.com/question/6536722

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3 0
3 years ago
suppose both the dog and the girl run at a speed of 2 m/s.Calculate both of there kinetic energies. kinetic energy of dog =
Andre45 [30]

Answer:

78

Explanation:

4 0
3 years ago
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8. John has to hit a bottle with a ball to win a prize. He throws a 0.4 kg ball with a velocity of 18 m/s. It hits a 0.2 kg bott
nasty-shy [4]

<u>Answer:</u> The ball is travelling with a speed of 5.5 m/s after hitting the <u>bottle.</u>

<u>Explanation:</u>

To calculate the speed of ball after the collision, we use the equation of law of conservation of momentum, which is given by:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m_1,u_1\text{ and }v_1 are the mass, initial velocity and final velocity of ball.

m_2,u_2\text{ and }v_2 are the mass, initial velocity and final velocity of bottle.

We are given:

m_1=0.4kg\\u_1=18m/s\\v_1=?m/s\\m_2=0.2kg\\u_2=0m/s\\v_2=25m/s

Putting values in above equation, we get:

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Hence, the ball is travelling with a speed of 5.5 m/s after hitting the bottle.

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c because it makes since

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