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IceJOKER [234]
2 years ago
11

You decide to walk part of the way around a lake. The lake is a circle with a radius of 2.0 km You start on the shore due south

of the lake and walk three-fourths of the way around the lake. ending up on the shore due east of the lake. What is your displacement?
Physics
1 answer:
AveGali [126]2 years ago
7 0

Answer:

2.828 km

Explanation:

radius of lake, r = 2 km

Let O be the centre of the circular lake and you walk from A to A to D.

Displacement is the measure of shortest distance between two points.

According to the diagram , the displacement AD is

AD^{2}=AO^{2}+OD^{2} (By using the Pythagorean theorem)

AD^{2}=2^{2}+2^{2}

AD = 2.828 km

thus, the displacement is 2.828 km.

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 Now let's determine how much kinetic energy needs to be dissipated. The equation is
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 E = 0.5 MV^2
 E = 0.5* 60 kg * (5 m/s)^2
 E = 0.5* 60 kg * 25 m^2/s^2
 E = 750 kg*m^2/s^2
 E = 750 J 
 Now let's divide the energy by the force.
 750 kg*m^2/s^2 / 366.8696226 kg*m/s^2 = 2.04432298 m
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