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frutty [35]
4 years ago
10

An igneous intrusion whose boundaries lie parallel to the layering in the surrounding country rock is considered to be:

Physics
1 answer:
ikadub [295]4 years ago
7 0
<span>...a concordant intrusion. In geology, "concordant" means the same as "sill" -- or, an intrusion that has gotten in between older layers of rock (or even beds of volcanic lava). An intrusion with boundaries parallel to layering in surrounding rocks suggests this, meaning it is considered to be a concordant intrusion.</span>
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A tennis ball is thrown horizontally at a speed of 10 m/s from the top of a building 78.4 meters high. how long does it take the
cupoosta [38]
When it comes to horizontal projectiles, the formula for time is:

t =  \sqrt{ \frac{2dy}{g} }

Where:
dy = vertical distance or height
g = acceleration due to gravity
t = time

Based on the problem, we know that the height at which the tennis ball was thrown is 78.4 m and the acceleration due to gravity is a constant 9.8m/s2. All you need to do is input that into our equation:
t = \sqrt{ \frac{2dy}{g} }
t = \sqrt{ \frac{(2)(78.4m)}{9.8m/s^{2}} }
t = \sqrt{ \frac{156.8m}{9.8m/s^{2}} }
t = \sqrt{16s^{2}}
t = 4s

The time it would take is 4 seconds.

7 0
4 years ago
Question 2 (3 points)
Whitepunk [10]
The electrical charge of the atom is 1.
4 0
3 years ago
A hurricanes energy comes from?
Shalnov [3]

Answer:

a or b

Explanation:

6 0
3 years ago
Read 2 more answers
A rotating merry-go-round makes one complete revolution in 4.0s a) what is the linear speed of a child seated 1.2 meters from th
lianna [129]

Answer:a) The linear speed of the rotating merry-go-round is 1.884 m/s.

b) The acceleration of the rotating merry-go-round  device is 2.95m/s^2.

Explanation:

a) linear speed of the device:

Distance =2\pi (r)

Child seated 1.2 meters from the center, which means that radius ,r = 1.2 meters

Time taken to complete one revolution = 4.0 seconds

\text{Linear speed}=v=\frac{distance}{time}=\frac{2\pi r}{t}=\frac{2\times 3.14\times 1.2 m}{4.0 s}=\frac{7.536 m}{4.0 s}=1.884 m/s

The linear speed of the rotating merry-go-round is 1.884 m/s.

b) Acceleration

Linear velocity ,v = 1.884 m/s

a_c=\frac{v^2}{r}

=\frac{1.884 m/s\times 1.884m/s}{1.2 m}=2.95m/s^2

The acceleration of the rotating merry-go-round  device is 2.95m/s^2.

7 0
4 years ago
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suter [353]

Answer:

Explanation:

The first diagram (by the left) is an endothermic reaction. In this reaction, the products are higher in energy than the reactants. Heat/Energy is absorbed in this reaction and enthalpy is positive. In second diagram (by the right) is an exothermic reaction. In this reaction, the reactants are higher in energy than the products. In this reaction, heat/energy is released.

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3 years ago
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