Answer:
1.54 m/s²
Explanation:
The free-fall acceleration is calculated as
g = w²r
Where w is the angular velocity of the satellite and r is the radius of the moon.
The angular velocity can be calculated as
Where T is the period, so
T = 110 min = 110 x 60 s = 6600 s
Then,
Finally, the radius of the moon is r = 1.7 x 10⁶ m, so the free-fall acceleration is
Therefore, the answer is 1.54 m/s²
<u>Out of all given choices, the following statements are true:</u>
- An ammeter is used to measure current.
- A voltmeter is used to measure voltage.
- A voltmeter must be placed in parallel with a resistor to measure the voltage across the resistor.
Options A, E, and F
<u>Explanation:</u>
An instrument by which the current in a circuit is measured is called ammeter whereas an instrument in which voltage is measured in a circuit is called a voltmeter . The ammeter is placed in series with the resistor while the voltmeter is placed in parallel with the resistor.
For the option B, since the ammeter must be placed in series with the resistor to measure current, it is false. Option C is false because an ammeter has zero internal resistance. Option D is also false because a voltmeter has a high internal resistance and is actually infinite.
ind the velocity my using the conservation of energy mgh=1/2mv^2. At the bottom, the mass is turning in a circle with tension pointing up towards the center of the circle and weight pointing down. Use the centripetal force requirement mv^2/r=T-W and solve for T. Hope this helps.
In every medical services rendered by a physician or
hospital, a financial obligation must be paid by the insurance or the patient. Each
patient is responsible to pay after each service for the professional fee, medical
equipment, facilities, supplies and any medical services incurred during the encounter.
Moreover, the payment collected from the insurance or
patient will be used in the medical industry where the cost of doing business
has doubled each year such as office space and clinic or hospital staffs.
Answer:
20654 N
Explanation:
Applying
F = kqq'/r²........... equation 1
Where F = Force between the charge, q = First charge, q' = second charge, r = distance betweeen the charge, k = coulomb's constant.
From the question,
Given: q = -0.0004 C, q' = 0.00092 C, r = 0.4 m
Constanr: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation 1
F = ( -0.0004×0.00092×8.98×10⁹)/(0.4²)
F = (3.30464×10³)/0.16
F = (3304.64)/0.16
F = 20654 N
Hence the force between the charges is 20654 N
