Answer:
<h3>473.8 m/s; 473.8 m/s</h3>
Explanation:
Given the initial velocity U = 670m/s
Horizontal velocity Ux = Ucos theta
Vertical component of the cannon velocity Uy = Usin theta
Given
U = 670m/s
theta = 45°
horizontal component of the cannonball’s velocity = 670 cos 45
horizontal component of the cannonball’s velocity = 670(0.7071)
horizontal component of the cannonball’s velocity = 473.757m/s
Vertical component of the cannonball’s velocity = 670 sin 45
Vertical component of the cannonball’s velocity = 670 (0.7071)
Vertical component of the cannonball’s velocity = 473.757m/s
Hence pair of answer is 473.8 m/s; 473.8 m/s
<h2><em>C. translational motion</em></h2><h2><em>HOPE IT HELPS !!!!!</em></h2>
Answer:
Check the diagram from the photo
Explanation:
Answer:
(1) tropical storm
(2) Severe tropical storm
(3) 305 kmh
The gravitational constant was experimentally measured by W Cavendish using the attraction between big and small lead balls. is true
The correct answer is true
<h3>How do you define gravitational constant?</h3>
the strength of gravity. a factor in use in Newton's gravity law to relate the strength of the gravitational pull between two bodies with their masses and distance from one another. 6.67259 X 10-11 newtons per square kilogram is roughly the gravitational constant. G is its identifier.
<h3> where is the strongest gravity is?</h3>
The gravitational pull of the earth is greatest near sea level, normally, and weakens as you get further from the center, such as to the summit of Mt. Everest. Because the obloid earth was slightly wider, but only by a minor ratio, the gravity just at poles is stronger than that at the equator.
To know more about gravitational constant visit:
brainly.com/question/858421
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