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Lesechka [4]
3 years ago
10

A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction

is mu_k. During time interval t, the sled moves a distance s, starting from rest.Find the average velocity vavg of the sled during that time interval.Express your answer in terms of the given quantities and, if necessary, appropriate constants. You may or may not use all of the given quantities.
Physics
1 answer:
lorasvet [3.4K]3 years ago
4 0

Answer:

The average velocity of the sled is vavg = s/t.

Explanation:

Hi there!

The average velocity is calculated as the traveled distance over time:

vavg = Δx/Δt

Where:

vavg = average velocity.

Δx = traveled distance.

Δt = elapsed time.

We already know the traveled distance (s) and also know the time it takes the sled to travel that distance (t). Then, the average velocity can be calculated as follows:

vavg = s/t

Have a nice day!

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Answer:

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Explanation:

We can find the angle of refraction by using Snell's law:

n_{1}sin(\theta_{1}) = n_{2}sin(\theta_{2})

Where:

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n₂: is the index of refraction of the medium 2 (diamond) = 2.42

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θ₂: is the angle of refraction =?

Hence, the angle of refraction is:

sin(\theta_{2}) = \frac{n_{1}sin(\theta_{1})}{n_{2}} = \frac{1.0003*sin(45)}{2.42} = 0.2922

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I hope it helps you!

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A glass ball of radius 3.74 cm sits at the bottom of a container of milk that has a density of 1.04 g/cm3. The normal force on t
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Answer:

The mass of the ball is 0.23 kg

Explanation:

Given that

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The bouncy force on the ball = Fb

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m=Mass of the ball = Density x volume

m = γ V    , γ =Density of the Ball

ρ V g  + N =  γ V g               ( take g= 10 m/s²)

\gamma =\dfrac{N+\rho V g}{V g}

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The mass of the ball is 0.23 kg

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