Answer:
541.14 m/s
Explanation:
We are given that
Mass of cannon=
Mass of shell,
Initial velocity of shell,v=547 m/s
We have to find the velocity of shell fired from this loose cannon.
According to law of conservation of momentum
Initial momentum of system=0
When the cannon is bolted to the ground then only shell moves and kinetic energy of system equals to kinetic energy of shell
Kinetic energy of shell,
K.E of shell=
K.E of shell=
K.E of shell=
2K.E of shell=
Velocity of shell fired from this loose cannon,v_2=
Hence, the velocity of shell fired from this loose cannon would be 541.14 m/s
Answer:
b. Research projects for a specific cause
Explanation:
Research funded by private foundations are usually for a specific cause. These type of research are usually properly scrutinized, and must have a high probability of success. Most of these projects may not be to benefit the consumers, but are usually done with a special purpose in mind.
<span>a. A solid will gain kinetic energy and become a liquid.</span>
Explanation:
Consider the kinematic equation,
where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,
through simple algebra we get
where this is the distance traveled in meters.
The first thing you should know is that the friction force is equal to the coefficient of friction due to normal force.
Therefore, clearing the normal force we have:
The friction is 565N.
(565 / 0.8) = 706.25N. weight.
