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3 years ago

Which statement about dwarf planets is true?

2 answers:

5 0

"Pluto was the first dwarf planet to be discovered" is the one statement among the following choices given in the question that is true <span>about dwarf planets. The correct option among all the options that are given in the question is the first option or option "a". Pluto was classified as a planet at first but in the year 1930 it was classified as a dwarf planet.</span>

Mila [183]3 years ago

4 0

Answer:

All dwarf planets likely contain a mixture of rock and ice

Explanation:

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Suppose a certain battery has an internal emf of 9.00 V but the potential difference across its terminals is only 80.0 % of that

Rudiy27

Answer:

$1140.48\times 10^{-6}J$

Explanation:

We have given that the battery has an internal emf of 9 volt

So E = 9 volt

Capacitance $C=44\mu F=44\times 10^{-6}F$

It is given that on the terminal voltage is only 80% of potential difference

So V = 0.8×9 = 7.2 volt

We know that energy stored in the capacitor is given by

$E=\frac{1}{2}CV^2=\frac{1}{2}\times 44\times 10^{-6}\times 7.2^2=1140.48\times 10^{-6}J$

8 0

3 years ago

Which component measures the potential difference across a branch in a circuit? A. switch B. resistor C. ammeter D. voltmeter

NNADVOKAT [17]

Answer:

Voltmeter

Explanation:

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3 years ago

Que actitud Tomárias si te sientes marginado

tresset_1 [31]

Buscar nuevos amigos, si no te quieren contigo o te ponen de lado, en realidad no son tus amigos o compañeros, nadie se merece eso, no necesitas esas personas en tu vida.

7 0

3 years ago

What is meant by the fact that length of a object is 4 metre

Luden [163]

Answer:

It simply means that the longest side of the object is 4 m that is 400cm..

Explanation:

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3 years ago

A scientist fixes a test charge q′ to point P and then measures the electrostatic force it experiences there. She then calculate

nordsb [41]

Answer:

<em>Correct answer: B.</em>

Explanation:

Electrostatic Field

It measures the electric effect of a charge distribution in its surroundings. If we wanted to test or measure the electric field by using a point-charge of value q', then the electric field is

$\displaystyle E=\frac{F}{q'}$

The electrostatic force between two point charges is

$\displaystyle F=\frac{k\ q_1\ q'}{r^2}$

So, the electric field is

$\displaystyle E=\frac{\frac{k\ q_1\ q'}{r^2}}{q'}$

$\displaystyle E=\frac{k\ q_1}{r^2}$

The theory shows that the electric field doesn't depend on the test charge used, i.e., if we now use q'=-q', the electric force will be of the same magnitude but in the opposite direction, thus the electric field will be the same. Let's recall the formula is used to compute the scalar value of the field, the direction must be studied separately.

Now, if we changed the test charge to another value, say 2q, the measured force will be

$\displaystyle F=\frac{k\ q_1\ 2q}{r^2}$

And the new electric field is

$\displaystyle E=\frac{k\ q_1}{r^2}$

We can see the electric field is not affected by the value of the test charge.

Finally, if we move the test charge to another location and keep the same charge, the electric force will vary and the electric field will be different.

Correct answer: B.

7 0

3 years ago