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Zina [86]
3 years ago
10

You ride your bike for a distance of 30 km. You travel at a speed of 0.75 km/ minute. How many minutes does this take?

Physics
2 answers:
My name is Ann [436]3 years ago
5 0

Answer:

Time taken, t = 40 minutes

Explanation:

Given that,

Distance covered, d = 30 km

Speed of the person, v = 0.75 km/min

Time taken by the person is given by :

t=\dfrac{d}{v}

t=\dfrac{30\ km}{0.75\ km/min}  

t = 40 minutes

So, the time taken by the person is 40 minutes. Hence, this is the required solution.

dolphi86 [110]3 years ago
4 0
(30 km)/(0.75 km/min) = 40 min
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63.4^{\circ}

Explanation:

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I_2 = \frac{1}{10}I_0

So we can rewrite (3) as

\frac{1}{10}I_0 =  \frac{1}{2}I_0 cos^2 \theta

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A bullet with mass m = 0.1 kg grams hits a ballistic pendulum with length L = 3 meters and mass M = 2 kg and lodges in it. When
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Answer:

e)     v₁ = 29.7 m / s

Explanation:

Let's propose the solution of the problem, let's start at the moment

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        p₀ = m v₁

Final

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The moment is preserved

      p₀ =  p_{f}

      m v₁ = (m + M) v

      v = m / (m + M) v₁        (1)

a) energy is conserved

Let's look for kinetic energy

Initial

      K₀ = ½ m v₁²

Final

      K_{f} = ½ (m + M) v²

Let's replace v

     K_{f} = ½ (m + M) [m / (m + M) v₁]²

      K_{f} = ½ m² / (m + M) v₁²

Let's look for the relationship of these energies

     Ko / K_{f} = ½ m v₁² / (½ m² / (m + M) v₁²)

     Ko / K_{f}= (m + M) / m = (1 + M / m)²

The kinetic energy changes therefore it is not conserved in the process, the missing energy is converted into potential heat energy during the crash

b) The impulse is conserved because the system is defined as formed by the two bodies and the externals are of action and reaction, so for the complete system the sum is zero and the moment does not change in value

c) in this case the system is already formed by the two bodies and since there is no rubbing the mechanical energy is conserved, transforming from kinetics to potential

d) when the pendulum oscillates the speed changes from v to zero, so the moment is not conserved, this is because there is an external force acting on the system, the force of gravity

e) For this part let's start at the end of the movement

It is system (bullet + block) moves, energy is conserved

Final. Highest point

          Em_{f} = U = (m + M) g h

Initial. Lowest point

          Em₀ = K = ½ (m + M) v2

          Em₀ =  Em_{f}

          ½ (m + M) v² = (m + M) g h

          v = √ 2gh

Let's look for the height (h) by trigonometry

         Cos 15 = x / L

          h = L-x

          h = L - L cos 15

          h = L (1- cos 15)

We replace

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Now we use equation (1) of momentum conservation

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         v₁ = (m + M) / m v

         v1 = (0.1 +2.0) /0.1 RA (2 9.8 3 (1- cos 15))

         v₁ = 21 √ (2.00)

        v₁ = 29.7 m / s

6 0
3 years ago
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