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den301095 [7]
3 years ago
7

How was the lunar regolith formed?

Physics
1 answer:
Gwar [14]3 years ago
7 0
It is formed by the impact of meteorites on the body’s surface. The force of the collision melts some of the impacted regolith to form objects.
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In the water cycle matter moves towards the pull of gravity during ??
Bumek [7]

infiltration and evaporation

7 0
3 years ago
Acceleration is defined as the rate of change for which of the following
Minchanka [31]
_Award brainliest if helped!
Velocity


Note : Not speed as Acceleration is a vector!
6 0
3 years ago
Jack drops a stone from rest off of the top of a bridge that is 24.4 m above the ground. After the stone falls 6.6 m, Jill throw
alukav5142 [94]
-17.555m/s

first I found the time it took for jacks stone to reach the bottom, using the formula vf = vi + at, vf and vi are final and initial velocities.

then i found the velocity at 6.6m using vf^2 = vi^2 + 2ad
and I found the time it took to get to 6.6m, so that I knew how long Jill waited to throw her stone, I used the formula d = t(vi+vf)/2, then i done total time - the time she waited, to get the time it took for there stones to hit the ground at the same time.

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4 0
2 years ago
You're in a car that gets 37 miles per gallon of gas, driving it at a constant speed. If you took the gas from the car tank, and
Sergeu [11.5K]

Answer:

Required diameter of hose pipe = 0.2864 mm

Solution:

From the continuity eqn, the fluid flow rate is given by:

Av = \frac{V}{t}

where

A = cross-sectional area = \pi r^{2}

r = hose pipe radius

v = velocity of gas

Also, v = \frac{displacement, d}{time, t}

Using:

1 gallon = 3.854 l

1 mile = 1609.34 m

1 m^{3} = 1000 l

Therefore,

A\frac{d}{t} = \frac{V}{t}

\pi r^{2} = \frac{V}{d}

\pi r^{2} = \frac{(1 gal).(\frac{3.7854 l}{gal}).(\frac{10^{- 3} m^{3}}{l})}{37 miles(\frac{1609.34 m}{miles})}

6.357\times 10^{- 8} = \pi r^{2}

r^{2} = 2.024\times 10^{- 8}

r = 1.423\times 10^{- 4} m = 0.1423 mm

The diameter of the hose pipe = 2r = 2\times 1.423\times 10^{- 4}

The diameter of the hose pipe = 2.846\times 10^{- 4} m = 0.2846 mm

4 0
3 years ago
7.
laiz [17]

7. Matthias Schleiden

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