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den301095 [7]
3 years ago
7

How was the lunar regolith formed?

Physics
1 answer:
Gwar [14]3 years ago
7 0
It is formed by the impact of meteorites on the body’s surface. The force of the collision melts some of the impacted regolith to form objects.
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Using the equation for decay, calculate the amount left of a radioactive sample amount N0 if the decay constant is 0.00125 secon
makkiz [27]

The amount left of a radioactive sample amount N0 if the decay constant is 0.00125 seconds and the time is 180 seconds is 0.7999 N.

<h3>What is half-life?</h3>

The time it takes for half of the original population of radioactive atoms to decay is called the half-life. The relationship between the half-life T1/2 and the decay constant is given by T1/2 = 0.693/λ.

  1. N=N0e−λt
  2. given λ = 0.00125 seconds
  3. t = 180 seconds
  4. Now putting values.
  5. N=N0e−λt = 0.799
  6. N= 0.7999.

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5 0
2 years ago
Which change increases the electric force between objects?
Brrunno [24]
Well, the force is proportional to the product of the charges
on the two objects.  So if the objects are already negatively
charged distance between them is unchanged, then adding
electrons to either or both objects would increase the forces
between them.

3 0
3 years ago
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What part of the hammer acts as the fulcrum when the hammer is used to remove a nail
Natali5045456 [20]
The end of it with the dent
6 0
3 years ago
A plane coming in to land at a busy airport is asked to circle the airport until the air traffic congestion eases off. The pilot
Ber [7]

Answer:

The solution is given in the picture attached below

Explanation:

8 0
3 years ago
In an inelastic collision a 2.5 kg ball moving at 7.5 m/s is caught by a 70kg man while the man is standing on ice. What is the
MrRa [10]

The velocity of the ball and the man is 0.259 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, in an isolated system, the total momentum before and after the collision must be conserved. Therefore, for the ball-man system, we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v

where:

m_1 = 2.5 kg is the mass of the ball

u_1 = 7.5 m/s is the initial velocity of the ball

m_2 = 70 kg is the mass of the man

u_2 = 0 is the initial velocity of the man

v is the final velocity of the man and the ball after the collision

Re-arranging the equation and substituting the values, we find the final velocity:

v=\frac{m_1 u_1}{m_1+m_2}=\frac{(2.5)(7.5)}{2.5+70}=0.259 m/s

So, the man and the ball slides on the ice at 0.259 m/s.

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