Answer: 71.43 kilograms
This value is approximate rounded to two decimal places.
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Explanation:
The ground is pushing up with a normal force of 700 N. Because the box is sitting still, this means the force of gravity is pulling the box down with a force of 700N to keep things balanced.
If the force of gravity was greater than 700N, then the box would fall through the ground. If the force of gravity was smaller than 700N, then the box would be accelerated upward. Since neither event is happening, the force of gravity must be equal to the normal force.
Now turn to Newton's second law which says
F = ma
where F is the force, m is the mass and 'a' is the acceleration. We're given the acceleration of gravity is roughly 9.80 m/s^2. So a = 9.80
The force we'll plug in is F = 700. The value of m is unknown, but we can solve for it as such
F = ma
700 = m*9.80
700 = 9.08m
9.80m = 700
m = 700/9.80
m = 71.4285714285714
m = 71.43
The mass is roughly 71.43 kilograms.
Velocity has direction but speed does not have direction
Answer:
Explanation:
It is given that,
Mass of the car 1,
Initial speed of the car 1,
Mass of the car 2,
Initial speed of the car 2,
It is mentioned that train cars are coupled together by being bumped into one another. Let V is the final velocity of the train cars after the collision. It can be calculated using the conservation of linear momentum as :
So, the final speed of the coupled train cars is 0.129 m/s towards x axis. Hence, this is the required solution.
Answer:
v = 120 m/s
Explanation:
We are given;
earth's radius; r = 6.37 × 10^(6) m
Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s
Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.
The angle will be;
θ = ¾ × 90
θ = 67.5
¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.
The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:
v = r(cos θ) × ω
v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)
v = 117.22 m/s
Approximation to 2 sig. figures gives;
v = 120 m/s
It could interact with each other.
Could be like plants getting energy from the sun