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Fittoniya [83]
3 years ago
14

A car is driving at 50 kilometers per hour. how far, in meters, does it travel in 2 seconds?

Physics
1 answer:
AveGali [126]3 years ago
7 0
<span>Sure, Just change the 2 sec. into hrs. Since 1 hour = 3600 sec. then you can divide 2/3600 = 1/1800 hrs. Distance in kilometers = (Speed in km/hr * time in hrs) = 50*(1/1800)*1000 in meters = 27.77 meters</span>
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A student walks 4 blocks east, 1 blocks north, 2 block west and then 1 blocks south in an hour. Her average velocity is?​
arsen [322]

Answer:

2 m/s

Explanation:

Given that a student walks 4 blocks east, 1 blocks north, 2 block west and then 1 blocks south in an hour.

The total time = 1 hour

The vertical displacement = 1 - 1

Vertical displacement = 0

Horizontal displacement = 4 - 2

Horizontal displacement = 2

Total displacement = sqrt (2^2 - 0^2)

Total Displacement = 2

Average velocity = displacement/time

average velocity = 2 / 1

Average velocity = 2 m/s

Therefore, her average velocity is 2 metres per second.

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How long would it take for 1.50 mol of water at 100.0 ∘c to be converted completely into steam if heat were added at a constant
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The total heat that is needed by the water to get converted to steam is calculated below through the equation,

     H = (Hv)(n)

where H is the heat, Hv is the heat of vaporization (40.67 kJ/mol), and n is the number of mols. Substituting the known values,

   H = (40.66 kJ/mol)(1.5 mol) = 60.99 kJ

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Answer: 2541.25 s or approximately 42.35 minutes
3 0
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A 0.017-kg acorn falls from a position in an oak tree that is 18.5 meters above the ground. Calculate the velocity of the acorn
sdas [7]

Answer:

The velocity of the acorn just before it reaches the ground is 19 m/s

The kinetic energy when hitting the ground is 3.1 J

Explanation:

Given;

mass of the acorn, m = 0.017 kg

height of fall, h = 18.5 m

Apply the law of conservation of mechanical energy;

mgh = ¹/₂mv²

gh = ¹/₂v²

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 18.5)

v = 19 m/s

Thus, the velocity of the acorn just before it reaches the ground is 19 m/s

Now, determine the kinetic energy when hitting the ground;

K.E = ¹/₂mv²

K.E = ¹/₂(0.017)(19)²

K.E = 3.09 J

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Therefore, the kinetic energy when hitting the ground is 3.1 J

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