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postnew [5]
3 years ago
9

Barry is conducting an experiment and rolls a tennis ball down a ramp. Which best describes the motion of the tennis ball? It do

es not exhibit projectile motion and follows a straight path down the ramp. It does not exhibit projectile motion and follows a parabolic path down the ramp. It exhibits projectile motion and follows a straight path down the ramp. It exhibits projectile motion and follows a parabolic path down the ramp.
Physics
2 answers:
yawa3891 [41]3 years ago
7 0

Answer:

A. It does not exhibit projectile motion and follows a straight path down the ramp.

puteri [66]3 years ago
4 0

Answer:

It does not exhibit projectile motion and follows a straight path down the ramp.

Explanation:

Projectile motion is the motion of the object that is projected into air. The only force acting on it must be the earth's gravity. The object projected into air is called the projectile and its path is called the trajectory.

In our case Barry is not throwing the tennis ball into air. It is just moving along the surface. It is just like any other movement on a flat surface The only difference it is happening at an angle.

In our case there is friction acting on the tennis ball, but only earth's gravity is supposed to act on the tennis ball.

So it does not exhibit projectile motion and follows a straight line path down the ramp

You might be interested in
Two violinists are trying to play in tune. However, whenever they play their A string at the same time they hear a beat frequenc
kaheart [24]

Answer:

The possible frequencies for the A string of the other violinist is 457 Hz and 467 Hz.

(3) and (4) is correct option.

Explanation:

Given that,

Beat frequency f = 5.0 Hz

Frequency f'= 462 Hz

We need to calculate the possible frequencies for the A string of the other violinist

Using formula of frequency

f'=f_{1}-f...(I)

f'=f_{1}+f...(II)

Where, f= beat frequency

f₁ = frequency

Put the value in both equations

f'=462-5=457\ Hz

f'=462+5=467\ Hz

Hence, The possible frequencies for the A string of the other violinist is 467 Hz and 457 Hz.

4 0
3 years ago
Assume that the upward direction is positive and the downward direction is negative. What is the ball's velocity (in m/s) when i
LenaWriter [7]

The given question is incomplete. The complete question is as follows.

You throw a ball vertically upward, and as it leaves your hand, its speed is 26.0 m/s.

(a) How high (in m) does it rise above the level where it leaves your hand?

(b) How long (in s) does it take to reach its highest point?

(c) How long (in s) does the ball take to return to the level where it left your hand after it reaches its highest point?

(d) Assume that the upward direction is positive and the downward direction is negative. What is the ball's velocity (in m/s) when it returns to the level where it left your hand? (Indicate the direction with the sign of your answer.)

Explanation:

(a) For maximum height, the formula will be as follows.

           v^{2} = u^{2} + 2as

                 a = v^{2} - 2gh

or,                 h = \frac{v^{2}}{2g}

                        = \frac{(26)^{2}}{2 \times 9.8}

                        = \frac{676}{19.6}

                        = 34.5 m/s

Hence, it rises 34.5 m/s above the level where it leaves your hand.

(b) Time to reach maximum height is as follows.

            v = u + at

or,           v - gt = 0

                 t = \frac{v}{g}

                   = \frac{26}{10}

                   = 2.6 sec

Therefore, it will take 2.6 sec to reach its highest point.

(c)  Time taken by the ball to ascent is equal to the time it has taken to descent.

Therefore, time taken by the ball to return to the level where it left your hand after it reaches its highest point? is also 2.6 sec.

(d)  Speed of the ball will be 26 m/s in the downward direction. Hence, the velocity will be -26 m/s.

3 0
3 years ago
Planet x has a mass of 4x1022 kg and a radius of 6x105 m What lise the grav ritational field strength in the surface of planet X
SCORPION-xisa [38]

Answer:

  g ≈ 7.4 m/s²

Explanation:

The acceleration due to gravity on planet XX is ...

  g = GM/r² = (6.67·10^-11 × 4·10^22)/(6·10^5)^2

  g ≈ 7.4 m/s²

6 0
3 years ago
What units are given to the right of the equals sign
zhuklara [117]
The answer

2y + 14 = 17

The 17 is to the right of the = sign
It is also the answer
7 0
3 years ago
Gravity is a force that every mass exerts on every other mass. When you jump up in the air, not only does the Earth exert a grav
sesenic [268]

Answer:

C. Your mass is very small compared to Earth's mass.

Explanation:

Newton's third law of motion states that:

"When an object A exerts a force (action force) on an object B, object B exerts an equal and opposite force (reaction force) on object A".

If we apply this law to the situation described in the problem, we see that:

- The action force is the gravitational force exerted by the Earth on you

- The reaction force is the gravitational force exerted by you on the Earth

And according to the 3rd law, the magnitude of the two forces is equal:

F_1 = F_2 (1)

We also know that, according to Newton's second law of motion, the force on an object is equal to the product between its mass (m) and its acceleration (a):

F=ma

So we can rewrite (1) as

ma = MA

where

m is the your mass

a is your acceleration

M is the Earth's mass

A is the Earth's acceleration

For the term on the left, we see that m is small, so a is larger (therefore, your acceleration is visible). However, for the term on the right, we see that the mass of the Earth is very large (M is very large), therefore, A is very small, which means that the acceleration of the Earth is almost negligible because the Earth's mass is very large.

4 0
4 years ago
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