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postnew [5]
3 years ago
9

Barry is conducting an experiment and rolls a tennis ball down a ramp. Which best describes the motion of the tennis ball? It do

es not exhibit projectile motion and follows a straight path down the ramp. It does not exhibit projectile motion and follows a parabolic path down the ramp. It exhibits projectile motion and follows a straight path down the ramp. It exhibits projectile motion and follows a parabolic path down the ramp.
Physics
2 answers:
yawa3891 [41]3 years ago
7 0

Answer:

A. It does not exhibit projectile motion and follows a straight path down the ramp.

puteri [66]3 years ago
4 0

Answer:

It does not exhibit projectile motion and follows a straight path down the ramp.

Explanation:

Projectile motion is the motion of the object that is projected into air. The only force acting on it must be the earth's gravity. The object projected into air is called the projectile and its path is called the trajectory.

In our case Barry is not throwing the tennis ball into air. It is just moving along the surface. It is just like any other movement on a flat surface The only difference it is happening at an angle.

In our case there is friction acting on the tennis ball, but only earth's gravity is supposed to act on the tennis ball.

So it does not exhibit projectile motion and follows a straight line path down the ramp

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2 years ago
A truck was carrying a substance in a tank. The molecules of that substance were moving away from each other. The truck parked o
DochEvi [55]

Answer:

In the morning the molecules were moving away from each other with a smaller speed than when the truck was carrying the substance.

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2 years ago
A 5 kg object near Earth's surface is released from rest such that it falls a distance of 10 m. After the object falls 10 m, it
makkiz [27]

Answer:D

Explanation:

Given

mass of object m=5 kg

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velocity acquired v=12 m/s

conserving Energy at the moment when object start falling and when it gains 12 m/s velocity

Initial Energy=mgh=5\times 9.8\times 10=490 J

Final Energy=\frac{1}{2}mv^2+W_{f}

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490=360+W_{f}

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3 years ago
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pickupchik [31]

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a = 1.86303*10^{13}m

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R = 1.86303*10^{13}(1-0.997)

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