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Stels [109]
3 years ago
15

A small object is attached to the end of a relaxed, horizontal spring whose opposite end is fixed. The spring rests on a frictio

nless surface. Let the initial position of the object be defined as x-0. The object is pulled to position x = A and then released, after which it undergoes simple harmonic motion.
In one full cycle of its motion, the total distance traveled by the object is:

1) A
2) A/2
3) 2A
4) 4A
5) A/4
Physics
1 answer:
eduard3 years ago
7 0

Answer:4A

Explanation:

Given

Mass is displace x= A units from its mean position x=0'

When it is set to free it will oscillate about its mean position with maximum amplitude A i.e. from x=-A to x=A

One cycle is completed when block returns to its original position

so first block will go equilibrium position x=0 and then to x=-A

from x=-A it again moves back to x=0 and finally back to its starting position x=A

so it travels a distance of A+A+A+A=4A    

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Answer:

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3 years ago
I need help with this question
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A pendulum has a length of 2 m and a 30 kg mass hanging on the end. What is the period of the
anastassius [24]

Answer:

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Explanation:

Hi!

The formula that you will want to use to solve this question is:

T = 2\pi *\sqrt{\frac{L}{g}  }

T--> period

L --> length of the pendulum

g --> acceleration due to gravity (9.8m/s^2)

since we know that the mass of the bob at the end of the pendulum does not affect the period of the pendulum, we can go ahead and ignore that bit of information (unless, of course, the weight causes the pendulum to stretch)

so now we can plug in our given info into the formula above and solve!

T = 2*pi * sqrt(2/9.8)

T = 2.83701481512 seconds

*Note*

- I used 3.14 to pi, if you need to use a different value for pi (a longer version, etc) your answer will be slightly different

I hope this helped!

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Answer:

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Explanation:

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