To develop this problem it is necessary to apply the concepts related to Work and energy conservation.
By definition we know that the work done by a particle is subject to the force and distance traveled. That is to say,
Where,
F= Force
d = Distance
On the other hand we know that the potential energy of a body is given based on height and weight, that is
The total work done would be given by the conservation and sum of these energies, that is to say
PART A) Applying the work formula,
PART B) Applying the height equation and considering that there is an angle in the distance of 25 degrees and the component we are interested in is the vertical, then
The net work would then be given by
Therefore the net work done by these 2 forces on the cannonball while it is in the cannon barrel is 3355J
Answer:
6.47385 N
Explanation:
m = Mass of stone = 0.538 kg
t = Time taken to hit the rock = 0.964 seconds
v = Velocity of rock = 11.6 m/s
Force is given by
The magnitude of the average force experienced by the boat during this process is 6.47385 N
Answer:
option (b)
Explanation:
B = 0.7 x 10^-4 T
v = 940 km/h = 940 x 5 / 18 = 261.11 m /s
l = 60 m
Th emotional emf is given by
e = B v l
e = 0.7 x 10^-4 x 261.11 x 60 = 1.096 V
e = 1.1 V
Answer:
the answer is 483.75 I believe
Answer:
16 m/s
Explanation:
First, find the displacement in the east direction.
x = (15 m/s sin 45°) (3600 s) + (18 m/s cos 5°) (3600 s)
x = 102,737 m
Next, find the displacement in the north direction.
y = (15 m/s cos 45°) (3600 s) + (18 m/s sin 5°) (3600 s)
y = 43,831 m
Find the magnitude of the displacement.
d = √(x² + y²)
d = √((102,737 m)² + (43,831 m)²)
d = 111,697 m
Finally, find the resultant velocity.
v = d / t
v = (111,697 m) / (7200 s)
v = 15.5 m/s
Rounded to the nearest whole number, the resultant velocity is 16 m/s.
