1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
faust18 [17]
2 years ago
5

If the air temperature is the same as the temperature of your skin (about 30 ∘C), your body cannot get rid of heat by transferri

ng it to the air. In that case, it gets rid of the heat by evaporating water (sweat). During bicycling, a typical 71.0 kg person’s body produces energy at a rate of about 502 W due to metabolism, 82.0 % of which is converted to heat. [Recall that the normal internal body temperature is 98.6 ∘F and the specific heat capacity of the body is 3480 J/(kg⋅∘C) .] How many kilograms of water must the person's body evaporate in an hour to get rid of this heat? The heat of vaporization of water at body temperature is 2.42 \times 10^6\;{\rm J/kg}.The evaporated water must, of course, be replenished, or the person will dehydrate. How many 750 {\rm mL} bottles of water must the bicyclist drink per hour to replenish the lost water? (Recall that the mass of a liter of water is 1.00 {\rm kg}.)
Physics
2 answers:
Neko [114]2 years ago
3 0

Answer:

In That Case, It Gets Rid Of The Heat By Evaporating Water (sweat). During Bicycling, A Typical 72.0 Kgperson's Body Produces Energy At A Rate Of About 501 W Due To Metabolism ... If the air temperature is the same as the temperature of your skin (about 30 ∘C), your body cannot get rid of heat by transferring it to the air.

Explanation:

skelet666 [1.2K]2 years ago
3 0

Answer:

m=0.612kg

0.8164 bottles

Explanation:  the last part of the question says

How many kilograms of water must the person's body evaporate in an hour to get rid of this heat? The heat of vaporization of water at body temperature is 2.42 \times 10^6\;{\rm J/kg}.The evaporated water must, of course, be replenished, or the person will dehydrate. How many 750 {\rm mL} bottles of water must the bicyclist drink per hour to replenish the lost water? (Recall that the mass of a liter of water is 1.00 {\rm kg}.)

Convert 500 watts to joules/sec.

That is 500 J/sec. The problem states about 80% is converted to heat so 500 J/sec x 0.8 = ?? heat produced in 1 sec.

How many J is that per hour.

502 J/sec x (60 sec/min) x (60 min/hour)

1807200J

Rcallit is 82% efficient

1481904J

q=mlv

q=heat produced by the body in Joules

m=mass of water loss

lv=latent eat of vaporization in

1481904J=m*2.42*10^6j/kg

m=0.612kg

the same as 0.612L

0.612l/0.750L/bottle

0.8164 bottles

You might be interested in
Question 8 of 10
-BARSIC- [3]

Answer:

The correct answer is the Convex lens. An image is formed when a ray of light coming from a point intersects at another point. The image is formed by the real intersection of light. The image is formed by the virtual intersection of Light.

here is the site : textbook.com

3 0
1 year ago
A student on her way to school walks eastward in a straight line 20.0 meters towards the bus stop, but realizes she dropped her
larisa [96]

Answer:

Total displacement will be 47 meter

Total distance will be 83 meters

Explanation:

We have given that first the student go eastward towards bus stop 20 meters

But he realizes that she dropped his physics notebook and so h=she turns back along the same way up to 18 meters

So displacement = 20-18 = 2 meters

And he travel 45 meters in east along the bus stop so total displacement = 45+2 = 47 meters

Total distance traveled by the student = 20+18+45 = 83 meters  

3 0
3 years ago
At the same moment, one rock is dropped and one is thrown downward with an initial velocity of 29m/s from the top of a building
Inessa [10]

Answer:

The thrown rock strike 2.42 seconds earlier.

Explanation:

This is an uniformly accelerated motion problem, so in order to find the arrival time we will use the following formula:

x=vo*t+\frac{1}{2} a*t^2\\where\\x=distance\\vo=initial velocity\\a=acceleration

So now we have an equation and unkown value.

for the thrown rock

\frac{1}{2}(9.8)*t^2+29*t-300=0

for the dropped rock

\frac{1}{2}(9.8)*t^2+0*t-300=0

solving both equation with the quadratic formula:

\frac{-b\±\sqrt{b^2-4*a*c} }{2*a}

we have:

the thrown rock arrives on t=5.4 sec

the dropped rock arrives on t=7.82 sec

so the thrown rock arrives 2.42 seconds earlier (7.82-5.4=2.42)

6 0
3 years ago
The force of attraction between a -165.0 uC and +115.0 C charge is 6.00 N. What is the separation between these two charges in m
Simora [160]

Answer:

  • The distance between the charges is 5,335.026 m

Explanation:

To obtain the forces between the particles, we can use Coulomb's Law in scalar form, this is, the force between the particles will be:

F = k \frac{q_1 q_2}{d^2}

where k is Coulomb's constant, q_1 and q_2 are the charges and d is the distance between the charges.

Working a little the equation, we can take:

d^2 = k \frac{q_1 q_2}{F}

d = \sqrt{ k \frac{q_1 q_2}{F}}

And this equation will give us the distance between the charges. Taking the values of the problem

k= 9.00 \ 10^9 \frac{N \ m^2}{C^2} \\q_1 = 165.0 \mu C \\q_2 = 115.0 C\\F=- 6.00

(the force has a minus sign, as its attractive)

d = \sqrt{ 9.00 \ 10^9 \frac{N \ m^2}{C^2} \frac{(165.0 \mu C) (115.0 C)}{- 6.00 \ N}}

d = \sqrt{ 9.00 \ 10^9 \frac{N \ m^2}{C^2} \frac{(165.0 \mu C) (115.0 C)}{- 6.00 \ N}}

d = \sqrt{ 28,462,500 \ m^2}}

d = 5,335.026 m

And this is the distance between the charges.

3 0
3 years ago
the temperature of a 2.0-kg increases by 5*c when 2,000 J of thermal energy are added to the block. What is the specific heat of
nata0808 [166]
To calculate the specific heat capacity of an object or substance, we can use the formula

c = E / m△T

Where
c as the specific heat capacity,
E as the energy applied (assume no heat loss to surroundings),
m as mass and
△T as the energy change.

Now just substitute the numbers given into the equation.

c = 2000 / 2 x 5
c = 2000/ 10
c = 200

Therefore we can conclude that the specific heat capacity of the block is 200 Jkg^-1°C^-1
3 0
3 years ago
Other questions:
  • If millikan was measuring the charge on an oil droplet with 3 negatively charged electrons on it, what charge would he have meas
    5·1 answer
  • A police car is at rest parallel to the highway and measures the speed of cars. It sends the signal with a frequency of 1200 Hz,
    15·1 answer
  • To describe velocity you need to know?
    15·2 answers
  • 2. A solid sphere and a solid cylinder, both uniform and of the same mass and radius, roll without slipping at the same forward
    10·1 answer
  • A physical (beam) is used to measure?​
    5·2 answers
  • Water exits straight down from a faucet with a 1.96-cm diameter at a speed of 0.55 m/s. The volume flow rate of the water as it
    15·1 answer
  • HELP ASAP!!!
    15·1 answer
  • Determine the resultant force exerted on an object if these three forces are exerted on it: F1=3.0N upwards,F2=6.0N at 45° to th
    13·1 answer
  • EDGE 2021 WILL GIVE BRAINLIEST
    8·1 answer
  • Forces come in pairs. What are these pairs called?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!