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mario62 [17]
4 years ago
6

The ________ and ________ are used to resolve vectors into their components.

Physics
1 answer:
forsale [732]4 years ago
7 0
The sin function and the cos function are used to resolve vectors into their componets
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A particular engine has a power output of 8 kW and an efficiency of 37%. If the engine expels 10994 J of thermal energy in each
VARVARA [1.3K]

Answer:

(a) 17450.8 J (B) 1.239 sec

Explanation:

We have given power output =8 KW

Heat expelled = 10994 j

Efficiency =37% = 0.37

(A) We know that efficiency \eta =1-\frac{heat\ expelled}{heat\ input}

0.37=1-\frac{10994}{heat\ input}

Heat input =17450.8 J

(B) Work done by the engine is = 17450.8-10994=6456.8 j

Power output is given by 8 KW =8000 W

So time for each cycle is \frac{8000}{6456.8}=1.239 sec

3 0
3 years ago
What happens to the gravitation force between two objects that are 15 m apart, when one of them moves 3 m closer?
TEA [102]

Answer:

It’s d

Explanation:

8 0
3 years ago
From a high tower one ball is dropped from rest and the second ball is simultaneously projected horizontally. Neglecting air res
leonid [27]

They will reach the ground at the same time.

Because where h is the height of the tower and g is acceleration due to gravity. Since for both the balls h and g are the same, the time must be the same hence both the balls will reach the ground at the same time.

8 0
3 years ago
How fast in m/s is the moon orbiting around the earth if it has orbital period of 27 days(2,330,800 seconds) and orbits at a rad
kobusy [5.1K]

Answer:

C = 2 pi R     circumference of orbit

V = C / P      speed of moon by dividing circumference by period of revolution

V = 2 pi R / P_ = 2 pi 3.8 * 10E8 m / 2.3308 * 10E6 sec = 1024 m/s

8 0
3 years ago
The place kicker on a football team kicks a ball from ground level with an initial speed of 4.00 m/s at an angle of 29.0° above
mafiozo [28]

Answer:

0.4 s

Explanation:

The time that the ball is in the air can be found with the next formula:

time = t = \frac{2v_{o}sen\beta}{g}

where v_{o} is the initial velocity of the ball, in this case:

v_{o}=4.00 m/s

β is the angle: β = 29.0°

And g is the acceleration of gravity: g=9.81m/s^2

Replacing all the values to find t, we have:

time = t = \frac{2(4m/s)sen(29)}{9.81m/s^2} = 0.4s

Thus, the ball is 0.4s in the air.

3 0
4 years ago
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