Answer:
(a) 17450.8 J (B) 1.239 sec
Explanation:
We have given power output =8 KW
Heat expelled = 10994 j
Efficiency =37% = 0.37
(A) We know that efficiency 

Heat input =17450.8 J
(B) Work done by the engine is = 17450.8-10994=6456.8 j
Power output is given by 8 KW =8000 W
So time for each cycle is 
They will reach the ground at the same time.
Because where h is the height of the tower and g is acceleration due to gravity. Since for both the balls h and g are the same, the time must be the same hence both the balls will reach the ground at the same time.
Answer:
C = 2 pi R circumference of orbit
V = C / P speed of moon by dividing circumference by period of revolution
V = 2 pi R / P_ = 2 pi 3.8 * 10E8 m / 2.3308 * 10E6 sec = 1024 m/s
Answer:
0.4 s
Explanation:
The time that the ball is in the air can be found with the next formula:

where
is the initial velocity of the ball, in this case:

β is the angle: β = 29.0°
And g is the acceleration of gravity: 
Replacing all the values to find t, we have:

Thus, the ball is 0.4s in the air.