All categories

3 years ago

Quien me ayuda en una tarea de matemáticas de una figura geométrica que no se cómo se llama

Physics

2 answers:

Ilia_Sergeevich [38]3 years ago

3 0

Answer:

i dont know what you mean

Explanation:

Vaselesa [24]3 years ago

3 0

Cómo se mira la figura?

You might be interested in

A 3.6-volt battery is used to operate a cell phone

Marina CMI [18]

Explanation :

It is given that,

Potential energy, $V=3.6\ V$

Power dissipated, $P=0.064\ Watt$

We know that the power dissipated is given by :

$P=VI$

I is the current passing through the phone.

$I=\dfrac{P}{V}$

$I=\dfrac{0.064\ W}{3.6\ V}$

$I=0.017\ A$

I = 0.018 A

Hence, the current that passes through the phone is (1) 0.018 A.

3 0

3 years ago

Read 2 more answers

A 75Kg man jumps from a window 1.0m above the sidewalk. If the man falls with his knees and ankles locked, the only cushion for

liq [111]

Answer:

150153.06122 N

Explanation:

m = Mass of person = 75 kg

h = Height of fall = 1 m

g = Acceleration due to gravity = 9.81 m/s²

F = Force

s = Displacement = 0.49 cm

Potential energy is given by

$P=mgh\\\Rightarrow P=75\times 9.81\times 1\\\Rightarrow P=735.75\ J$

Work is given by

$W=Fs\\\Rightarrow F=\frac{W}{s}\\\Rightarrow F=\frac{735.75}{0.0049}\\\Rightarrow F=150153.06122\ N$

The average force exerted is 150153.06122 N

8 0

3 years ago

When sweat evaporates from your skin the temp of your skin decreases this is because

Vanyuwa [196]

The water molecules with a slower speed are escaping

8 0

3 years ago

There is a force which resists changes in motion, called

adoni [48]

Answer:

inertia 11

Explanation:

5 0

3 years ago

A 225-g object is attached to a spring that has a force constant of 74.5 N/m. The object is pulled 6.25 cm to the right of equil

snow_lady [41]

Answer:

1.137278672 m/s

+5.9 cm or -5.9 cm

Explanation:

A = Amplitude = 6.25 cm

m = Mass of object = 225 g

k = Spring constant = 74.5 N/m

Maximum speed is given by

$v_m=A\omega\\\Rightarrow v_m=A\sqrt{\dfrac{k}{m}}\\\Rightarrow v_m=6.25\times 10^{-2}\times \sqrt{\dfrac{74.5}{0.225}}\\\Rightarrow v_m=1.137278672\ m/s$

The maximum speed of the object is 1.137278672 m/s

Velocity is at any instant is given by

$\dfrac{v_m}{3}=\omega\sqrt{A^2-x^2}\\\Rightarrow \dfrac{A\omega}{3}=\omega\sqrt{A^2-x^2}\\\Rightarrow \dfrac{A}{3}=\sqrt{A^2-x^2}\\\Rightarrow \dfrac{A^2}{9}=A^2-x^2\\\Rightarrow A^2-\dfrac{A^2}{9}=x^2\\\Rightarrow x^2=\dfrac{8}{9}A^2\\\Rightarrow x=A\sqrt{\dfrac{8}{9}}\\\Rightarrow x=6.25\times 10^{-2}\sqrt{\dfrac{8}{9}}\\\Rightarrow x=\pm 0.0589255650989\ m$

The locations are +5.9 cm or -5.9 cm

4 0

2 years ago

Quien me ayuda en una tarea de matemáticas de una figura geométrica que no se cómo se llama​

Quien me ayuda en una tarea de matemáticas de una figura geométrica que no se cómo se llama