Answer: Oxygen, Beryllium, Lithium, & Fluorine
Explanation:
theoretically it might not be the answer be
Answer:
First convert volume given into same unit.
Therefore 1000 mL =1L
1000mL=1L
25.0mL=?
(25.0×1)÷1000=0.025L
but using the equation;M1×V1=M2×V2
M1=14.2M
V1=0.025L
M2=?
V2=0.5L
Therefore;. 14.2×0.025=M2×0.5
M2=(14.2×0.025)÷0.5
M2=0.71M.
Answer:
The energy required is 3225 Joules.
Explanation:
Given,
mass of lead cube = 500 grams
T₁ = 25°C
T₂ = 75°C
specific heat of lead = 0.129 J/g°C
Energy required to heat the lead can be found by using the formula,
Q = (mass) (ΔT) (Cp)
Here, ΔT = T₂ - T₁ = 75 - 25 = 50
Substituting the values,
Q = (500)(50)(0.129)
Q = 3225 Joules.
Therefore, energy required is 3225 J.
Answer:
b
Explanation:
beacuse when u reduce the concentration