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3 years ago

Which statement describes the difference between speed and velocity

2 answers:

7 0

Velocity is speed plus a direction.

30 miles per hour to the north
30 miles per hour to the east

These are the same speed but different velocities.

expeople1 [14]3 years ago

3 0

Explanation :

Distance : The total path covered during the entire journey of any particle.

Displacement : The smallest path covered by a particle.

Speed : It is defined as the total distance covered divided by total time taken. It has only magnitude not direction.

Velocity : It is defined as the total displacement traveled by a particle divided by total time taken. It is a vector quantity. It has both magnitude and direction.

Hence, the correct option is (A) " Velocity is speed with a direction".

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A racehorse is running with a uniform speed of 69 km/hr along a straightaway. what is the time it takes for the horse to cover 4

Alex

Hello there,
400 meters= 0.4 km
Time= Distance / speed
= 0.4 / 69
= 0.0057971014492754 hr
= 0.35 min

Hope this helps :))

~Top

8 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST!

boyakko [2]

It’s mass is 100 kg, because if you divide both numbers, you get 100

6 0

3 years ago

An airplane is being pushed West by its engines with a force of 350 N as it starts to take off the runway at the Atlanta airport

Marizza181 [45]

Answer:

option C

Explanation:

given,

Force by the engine on plane in West direction = 350 N

Frictional force on the runway = 100 N in east

force exerted by the wind = 100 N in east

net force and direction = ?

consider west to be positive and east be negative.

when airplane will be moving there will be frictional as well as wind resistance will be acting in opposite direction of airplane

Net force = 350 N - 100 N - 100 N

= 150 N

as our answer comes out to be positive so the airplane will be moving in West

hence, the correct answer is option C

8 0

2 years ago

A runner is moving at a constant speed of 8.00 m/s around a circular track. If the distance from the runner to the center of the

Genrish500 [490]

Answer: Last option

2.27 m/s2

Explanation:

As the runner is running at a constant speed then the only acceleration present in the movement is the centripetal acceleration.

If we call a_c to the centripetal acceleration then, by definition

$a_c =w^2r = \frac{v^2}{r}$

in this case we know the speed of the runner

$v =8.00\ m/s$

The radius "r" will be the distance from the runner to the center of the track

$r = 28.2\ m$

$a_c = \frac{8^2}{28.2}\ m/s^2$

$a_c = 2.27\ m/s^2$

The answer is the last option

3 0

3 years ago

A car is traveling north at 17.7 m/s . After 6 it’s velocity is 141 in the same direction. Find the magnitude and direction of t

Furkat [3]

By equation of motion we have v = u + at

Where u = Initial velocity, v = final velocity, t = time taken and a = acceleration

Here v = 141 m/s, u = 17.7 m/s and t = 6 s

On substitution we will get

141 = 17.7+ 6a

So, a = (141-17.7)/6 = 20. 55 m/ $s^{2}$

Aceeleration = 20. 55 m/ $s^{2}$ along north direction.

3 0

3 years ago