Both the acetamido (-NHCOCH3) and bromo (-Br) substituents are ortho, para directors. Even though the acetamido group is much la
rger than the bromo group, the -Cl is still introduced next to the acetamido group in spite of the greater steric hinderance at this site. Why?
1 answer:
Answer:
Explanation has been given below
Explanation:
- Attachment of -Cl group at ortho position to acetamido group can be explained in terms of hydrogen bonding formation.
- A hydrogen bonding can be formed between proton attached with N atom in acetamido group and Cl atom at ortho position. This leads to a formation of a stable 5-membered ring structure.
- Hence ortho substitution by Cl is favorable process.
- There is no hydrogen bonding possible between Br and Cl atom in ortho position. Therefore Cl prefers para position to avoid steric hindrance.
- Structure of hydrogen bonded structure has been shown below.
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The percent yield of copper hydroxide is 84%
<h3>Stoichiometry</h3>From the question, we are to determine the percent yield of copper hydroxide
First, we will determine the theoretical mass
From the given balanced chemical equation, we have
Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃
This means,
1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide
Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide
The theoretical number of moles of copper hydroxide that is produced is 0.05 mole
Now, for the theoretical mass
Using the formula,
Mass = Number of moles × Molar mass
Molar mass of copper hydroxide = 97.56 g/mol
Then,
Theoretical mass = 0.05 × 97.56
Theoretical mass of copper of hydroxide produced is = 4.878 g
Now, for the percent yield of copper hydroxide
Percent yield is given by the formula,
Then,
Hence, the percent yield of copper hydroxide is 84%.
Learn more on Stoichiometry here: brainly.com/question/9372758