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3 years ago

2. 10.36 g of Cu reacts with silver (1) nitrate to produce solid silver and copper (II) nitrate. How many

Chemistry

1 answer:

Basile [38]3 years ago

6 0

Answer:

Explanation:

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Why do you think learning about how atomic theory has evolved is important?

tatuchka [14]

I feel like it is important, because it is always nice to learn about new things and keep your mind open, to expand your knowledge.

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3 years ago

In The Lord of the Rings, Frodo and Sam use a rope to rappel down a cliff. The rope was 30 ells long. How high was the cliff in

Tcecarenko [31]

Answer:

324 meters

Explanation:

I don't really have an explanation

7 0

2 years ago

If you reacted 93.7 grams of iron with excess copper sulfate solution, what mass of copper would you expect to make? you may nee

Mariana [72]

Answer is although the question should have 3 significant figures.

<h3>What is significant figures?</h3>

Chemical equation

Fe + CuSO4 --> Cu + FeSO4

It is already balanced

Molar ratios

1 mol Fe : 1 mol CuSO4 : 1 mol Cu : 1 mol FeSO4

atomic masses of Fe and Cu

Fe: 55.8 g/mol

Cu: 63.5 g/mol

number of moles of Fe

number of moles = mass in grams / atomic mass = 93.7 g / 55.8 g/mol = 1.679 mol

number of moles of Cu:

1 mol Fe / 1 mol Cu => 1.679 mol Fe / 1.679 mole Cu

mass of Cu in 1.679 moles Cu

mass = atomic mass * number of atoms = 63.5 g/mol * 1.679 moles = 106.6 g = 107 rounded to 3 significant figures.

To learn more about significant figures, refer to:

brainly.com/question/24491627

#SPJ4

3 0

1 year ago

I need help Immediately oleae

Burka [1]

Answer:

B) atom 1 and atom 4

Explanation:

5 0

3 years ago

At a certain temperature the value of the equilibrium constant, Kc, is 1.27 for the reaction. 2As (s) + 3H2 (g) ⇌ 2AsH3 (g) What

Bess [88]

Answer:

$0.887$

Explanation:

Hello,

In this case, the law of mass action for the first reaction turns out:

$Kc=\frac{[AsH_3]^2}{[As]^2[H_2] ^3}=1.27$

Now, for the second reaction is:

$Kc=\frac{[As][H_2] ^{3/2}}{[AsH_3]}$

Therefore, by applying square root for the first reaction, one obtains:

$\sqrt{Kc} =\sqrt{\frac{[AsH_3]^2}{[As]^2[H_2] ^3}} =\sqrt{1.27}$

$\frac{\sqrt{[AsH_3]^2} }{\sqrt{[As]^2} \sqrt{[H_2] ^3} } =\sqrt{1.27}$

$\sqrt{1.27}=\frac{[AsH_3]}{[As][H_2] ^{3/2}}$

Finally, since Kc is asked for the inverse reaction, one modifies the previous equation as:

$Kc'=\frac{1}{\sqrt{1.27} }=\frac{[As][H_2] ^{3/2}}{[AsH_3]}=0.887$

Best regards.

8 0

3 years ago