Answer:
Explanation:
velocity is the rate of change of displacement with respect to time.
Velocity = displacement/time
If a line runs straight from 0 seconds 5 meters to 10 seconds 30 meters.
The velocity will be expressed as;
v = d2-d2/t2-t1
v = 30-5/10-0
v = 25/10
v = 2.5m/s
Hence her velocity is 2.5m/s
- Mass=m=10kg
- Radius=r=2m
- Speed=v=50m/s
Force:-
![\\ \rm\hookrightarrow F_c=\dfrac{mv^2}{r}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5Chookrightarrow%20F_c%3D%5Cdfrac%7Bmv%5E2%7D%7Br%7D)
![\\ \rm\hookrightarrow F_c=\dfrac{10(50)^2}{2}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5Chookrightarrow%20F_c%3D%5Cdfrac%7B10%2850%29%5E2%7D%7B2%7D)
![\\ \rm\hookrightarrow F_c=5(2500)](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5Chookrightarrow%20F_c%3D5%282500%29)
![\\ \rm\hookrightarrow F_c=12500](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5Chookrightarrow%20F_c%3D12500)
Now using Newton's second law
![\\ \rm\hookrightarrow A_c=\dfrac{F_c}{m}=\dfrac{12500}{10}=1250m/s^2](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5Chookrightarrow%20A_c%3D%5Cdfrac%7BF_c%7D%7Bm%7D%3D%5Cdfrac%7B12500%7D%7B10%7D%3D1250m%2Fs%5E2)
Answer:
6.17 m
Explanation:
We are given that
Initial speed of rubber ball, u=12 m/s
Total height, h=7 m
Initial speed of second ball, u'=0
We have to find the height at which the two balls collide.
Let first rubber ball and second ball strikes after t time.
For first ball
Distance traveled by first ball in time t
![S=ut-\frac{1}{2}gt^2](https://tex.z-dn.net/?f=S%3Dut-%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
Substitute the value
![S=12t-\frac{1}{2}(9.8)t^2](https://tex.z-dn.net/?f=S%3D12t-%5Cfrac%7B1%7D%7B2%7D%289.8%29t%5E2)
...(1)
Distance traveled by second ball in time t
![7-S=\frac{1}{2}(9.8)t^2](https://tex.z-dn.net/?f=7-S%3D%5Cfrac%7B1%7D%7B2%7D%289.8%29t%5E2)
.....(2)
Using equation (2) in equation (1) we get
![S=12t-(7-S)](https://tex.z-dn.net/?f=S%3D12t-%287-S%29)
![S=12t-7+S](https://tex.z-dn.net/?f=S%3D12t-7%2BS)
![\implies 12t=7](https://tex.z-dn.net/?f=%5Cimplies%2012t%3D7)
sec
Now, using the value of t
![S=12(\frac{12}{7})-4.9(\frac{12}{7})^2](https://tex.z-dn.net/?f=S%3D12%28%5Cfrac%7B12%7D%7B7%7D%29-4.9%28%5Cfrac%7B12%7D%7B7%7D%29%5E2)
S=6.17 m
Hence, at height 6.17 m the two balls collide .
It is a passive electronic that stores energy
Ionic solute surrounded by polar solvent