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Gemiola [76]
3 years ago
12

Which shows a vector quantity in the given situation. The airplane was flying 500 miles per hour to west from New York to Califo

rnia
a. 500 miles/hr West
b. 500 miles only
c. 500 miles from New York
d. 500 miles /hr
Physics
2 answers:
jenyasd209 [6]3 years ago
4 0

500 miles/hr West

Because it has magnitude and direction

Nezavi [6.7K]3 years ago
3 0
A. 500 miles/hr West
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Determine the work done by 2. 00 kg of water when it is all boiled to steam at 100 ∘c. Assume a constant pressure of 1. 00 atm.
neonofarm [45]

The work done by the water at the constant pressure is -4.52 \times 10^6 \ J.

<h3>Heat required to boil the water</h3>

The heat required to boil the water is calculated as follows;

Q = mL_v\\\\

where;

  • L_v is the heat of vaporization of water = 22.6 x 10⁵ J/kg
  • m is mass of water

Q = 2 \times 22.6 \times 10^5\\\\Q = 4.52 \times 10^6 \ J

<h3>Work done by the water</h3>

The work done by the water at the constant pressure is equal to the heat gained by the water.

W = - \Delta H\\\\W = -4.52 \times 10^6 \ J.

Learn more about first law of thermodynamics here: brainly.com/question/2965070

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How much water is stored in groundwater lakes rivers soil and streams
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Answer:

Explanation:

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What does the term Milankovitch cycles most closely relate to?
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The term Milankovitch cycles most closely relate to periodic changes in Earth’s orbit and angle of tilt relative to sun. So for this question, the correct option is option “c”. Milankovitch affects actually deals with the effect of the changes in the earth’s movements with the change in the climatic conditions. Milankovitch was a Serbian geophysicist and also a great astronomer. His studies actually helped in relating the climatic changes with the changes in the tilt of the earth. He was the first person to mathematically prove this situation.


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4 years ago
A 10-gram aluminum cube absorbs 677 joules when its temperature is increased from 50°c to 125°
kotegsom [21]

Answer : The specific heat of aluminum is, 0.90J/g^oC

Solution : Given,

Heat absorbs  = 677 J

Mass of the substance = 10 g

Final temperature = 125^oC

Initial temperature = 50^oC

Formula used :

Q= m\times c\times \Delta T

or,

Q= m\times c\times (T_{final}-T_{initial})

Q = heat absorbs

m = mass of the substance

c = heat capacity of aluminium

T_{final} = final temperature

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Now put all the given values in the above formula, we get the specific heat of aluminium.

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Therefore, the specific heat of aluminum is, 0.90J/g^oC

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