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bekas [8.4K]
3 years ago
14

Puck 1 (1 kg) travels with velocity 20 m/s to the right when it collides with puck 2 (1 kg) which is initially at rest. After th

e collision, puck 1 moves with a velocity of 5 m/s. Assume that no external forces are present and therefore the momentum for the system of pucks is conserved. What is the final velocity (in m/s) of puck 2 after the collision
Physics
1 answer:
Burka [1]3 years ago
7 0

Answer:

Explanation:

Parameters given:

Mass of Puck 1, m = 1 kg

Mass of Puck 2, M = 1 kg

Initial velocity of Puck 1, u = 20 m/s

Initial velocity of Puck 2, U = 0 m/s

Final velocity of Puck 1, v = 5 m/s

Since we are told that momentum is conserved, we apply the principle of conservation of momentum:

Total initial momentum of the system = Total final momentum of the system

mu + MU = mv + MV

(1 * 20) + (1 * 0) = (1 * 5) + (1 * V)

20 = 5 + V

V = 20 - 5 = 15 m/s

Puck 2 moves with a velocity of 15 m/s

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\Delta d = d_f - d_i

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(a) ∆<em>d</em> = 5 m - 0 m = 5 m

(b) ∆<em>d</em> = 1 m - (-2 m) = 1 m + 2 m = 3 m

(c) ∆<em>d</em> = 2 m - (-2 m) = 2 m + 2 m = 4 m

(d) ∆<em>d</em> = 6 m - 2 m = 4 m

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Answer:

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Explanation:

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Explanation:

Sorry if this isn't what you meant or were looking for.

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