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bekas [8.4K]
3 years ago
14

Puck 1 (1 kg) travels with velocity 20 m/s to the right when it collides with puck 2 (1 kg) which is initially at rest. After th

e collision, puck 1 moves with a velocity of 5 m/s. Assume that no external forces are present and therefore the momentum for the system of pucks is conserved. What is the final velocity (in m/s) of puck 2 after the collision
Physics
1 answer:
Burka [1]3 years ago
7 0

Answer:

Explanation:

Parameters given:

Mass of Puck 1, m = 1 kg

Mass of Puck 2, M = 1 kg

Initial velocity of Puck 1, u = 20 m/s

Initial velocity of Puck 2, U = 0 m/s

Final velocity of Puck 1, v = 5 m/s

Since we are told that momentum is conserved, we apply the principle of conservation of momentum:

Total initial momentum of the system = Total final momentum of the system

mu + MU = mv + MV

(1 * 20) + (1 * 0) = (1 * 5) + (1 * V)

20 = 5 + V

V = 20 - 5 = 15 m/s

Puck 2 moves with a velocity of 15 m/s

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A person hears the echo of his own voice from a distant hill after 2 seconds. How far away is the person from the hill, if the s
olga nikolaevna [1]

Answer: 330 m

Explanation:

The speed of sound V is defined as the distance traveled by the sound wave d in a especific time t:  

V=\frac{d}{t}  

Where:  

V=330 m/s is the speed of sound  

t=\frac{2 s}{2}=1 s is half the time the sound wave travels since the person speaks, the sound wave hits the hill and then returns to the person again  as an echo

d is the distance between the person and the hill

So, we have to find d:

d=Vt

d=(330 m/s)(1 s)

Finally:

d=330 m

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Hey there, the answer is ..............................  About 0.7 m/sec^2
<span>
Acceleration is the change in speed / time </span>

<span>Change in speed is 60 m/sec </span>

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<span>Divide the change in speed by the time in seconds.

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