The frequency of rotation of Mars is 0.0000113 Hertz.
<u>Given the following data:</u>
- Period = 1 day and 37 minutes.
To find the frequency of rotation in Hertz:
First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.
<u>Conversion:</u>
1 day = 24 hours
24 hours to minutes = 
× 
= 
minutes
1 minute = 60 seconds
1477 minute = X seconds
Cross-multiplying, we have:
× 
X = 88620 seconds
Now, we can find the frequency of rotation of Mars by using the formula:
<em>Frequency </em><em>of rotation</em> = <em>0.0000113 Hertz</em>
Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.
Read more: brainly.com/question/14708169
Answer:
I. 0 m/s
II. 20 m/s
III. Part BC
Explanation:
I. Determination of the initial velocity.
From the diagram given above,
The motion of the car starts from the origin. This implies that the car start from rest and as such, the initial velocity of the car is 0 m/s
II. Determination of the maximum velocity attained.
From the diagram given above, we can see clearly that the maximum velocity is 20 m/s.
III. Determination of the part of the graph that represents zero acceleration.
It important that we know the meaning of zero acceleration.
Zero acceleration simply means the car is not accelerating. This can only be true when the car is moving with a constant velocity.
From the graph given above, the car has a constant velocity between B and C.
Therefore, part BC illustrates zero acceleration.
Answer:
4.2 J
Explanation:
Specific heat capacity: This is defined as the amount of a heat required to rise a unit mass of a substance through a temperature of 1 K
From specific heat capacity,
Q = cmΔt.............................. Equation 1
Where Q = amount of energy absorbed or lost, c = specific heat capacity of water, m = mass of water, Δt = Temperature rise.
Given: m = 1 g = 0.001 kg, Δt = 1 °C
Constant : c = 4200 J/kg.°C
Substitute into equation 1
Q = 0.001×4200(1)
Q = 4.2 J.
Hence the energy absorbed or lost = 4.2 J
100.000 kilometres, it takes half an hour.
