1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NISA [10]
3 years ago
5

A Carnot engine operates with a cold reservoir at a temperature of 474 K and a hot reservoir at a temperature of 628 K. What is

the net entropy change (in J/K) as it goes through a complete cycle? slader
Physics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

zero

Explanation:

A Carnot engine is an ideal engine in which the process is cyclic and reversible.

A Carnot engine is the engine whose efficiency is 100 % and the entropy in is equal to entropy out. That means the net change in entropy is zero.

You might be interested in
Plzz helpppp meee!!!!
spin [16.1K]
A=f/m
A=900/425
A=2.18

To determine acceleration you divide the force by the mass.
4 0
2 years ago
Read 2 more answers
What impact can a very large volcanic eruption have on earths climate
Vaselesa [24]

Answer:

  1. It could instantly kill all life on Earth
  2. It could block out the sun and kill off all plants
  3. It could block out the sun and freeze everything
  4. It could throw sulfur millions of miles and kill everything that 'inhales' it
8 0
3 years ago
What is the source of waves​
Wittaler [7]

Answer:

the ocean

Explanation:

the ocean I think

7 0
2 years ago
Read 2 more answers
In one experiment the electric field is measured for points at distances r from a uniform line of charge that has charge per uni
Yuki888 [10]

Answer:

(a) A. Uniform line of charge and B. Uniformly charged sphere

(b) To three digits of precision:

λ = 1.50 * 10^-10 C/m

p = 2.81 * 10^-4 C/m^3

Explanation:

8 0
3 years ago
A 5 kg box drops a distance of 10 m to the ground. If 70% of the initial potential energy goes into increasing the internal ener
Elina [12.6K]

Answer:

Explanation:

From the given information:

The initial PE (PE)_i = m×g×h

= 5 kg × 9.81 m/s² × 10 m

= 490.5 J

The change in Potential energy P.E of the box is:

ΔP.E = P.E_f -P.E_i

ΔP.E = 0 - (PE)_i

ΔP.E = -P.E_i

If we take a look at conservation of total energy for determining the change in the internal energy of the box;

\Delta P.E + \Delta K.E + \Delta U = 0

\Delta U = -\Delta P.E - \Delta K.E

this can be re-written as:

\Delta U =- (-\Delta P.E_i) - \Delta K.E

Here, K.E = 0

Also, 70% goes into raising the internal energy for the box;

Thus,

\Delta U =(70\%) \Delta P.E_i-0

\Delta U =(0.70) (490.5)

ΔU = 343.35  J

Thus, the magnitude of the increase is = 343.35 J

7 0
3 years ago
Other questions:
  • A ball of mass m and radius R is both sliding and spinning on a horizontal surface so that its rotational kinetic energy equals
    11·1 answer
  • Why can scientists ignore the gravitational force when studying the physics of an atom?
    12·1 answer
  • Determine the linear velocity of an object with an angular velocity of 5.9 radians per second at a distance of 12 centimeters fr
    15·1 answer
  • What layer of the atmosphere is made mostly of hydrogen and helium?
    8·1 answer
  • My Notes Ask Your The speed of light is now defined to be c= 2.99792458*101 mis. (a) Express the speed of light to three signifi
    11·1 answer
  • A 49-year-old female was referred for mammography, but she is very apprehensive after reading about the risk of ionizing radiati
    7·1 answer
  • A 4kg box accelerated from rest by a force across the floor at a rate of 2m/s^2 for 7 seconds. What is the net work done on the
    14·2 answers
  • Please help me I only have a few questions and need this turned in by the end of the day! In all of our simulations we left the
    15·2 answers
  • An amusement park ride called the Rotor debuted in 1955 in Germany. Passengers stand in the cylindrical drum of the Rotor as it
    6·1 answer
  • Q: Explain the shape of the I-V graph of the filament lamp?<br>​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!