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NISA [10]
3 years ago
5

A Carnot engine operates with a cold reservoir at a temperature of 474 K and a hot reservoir at a temperature of 628 K. What is

the net entropy change (in J/K) as it goes through a complete cycle? slader
Physics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

zero

Explanation:

A Carnot engine is an ideal engine in which the process is cyclic and reversible.

A Carnot engine is the engine whose efficiency is 100 % and the entropy in is equal to entropy out. That means the net change in entropy is zero.

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Object A weighs 750 N on earth. Object B weighs 750 N on Jupiter.
Katarina [22]

The object A has the greater mass compared to object B.

<u>Explanation: </u>

The weight of any object on any planet is the measurement of gravity’s influence acting on the mass of the object. So for Earth, the acceleration will be acting on the object A’s mass (m) in Earth leading to the weight of the object A as 750 N.

While the acceleration of Jupiter will be acting on the object B’s mass kept in Jupiter to attain the weight of 750 N. So, the mass of both the objects at their respective planet will vary depending on the acceleration of each planet. We can check this as below:

            \text { object A's weight }=\text { m of object A } \times \text { Acceleration of Earth}

So,

           750 \mathrm{N}=\text { m of object } A \times 9.8 \mathrm{m} / \mathrm{s}^{2}

Thus,

          \text { m of object } A=\frac{750}{9.8}=76.5 \mathrm{kg}

Similarly for object B,

          \text { Weight of object } B=m \text { of object } B \times \text { Acceleration due to gravity of Jupiter }

          750 = m \text { of object } B \times 24.79 \mathrm{m} / \mathrm{s}^{2}

Thus,

          \text { m of the object } B=\frac{750}{24.79}=30.25 \mathrm{kg}

Thus, the mass of object A is greater than the mass of object B.

5 0
4 years ago
A crate which has a mass of m1 = 125kg is sitting on an icy surface. A rope is attached to the crate and held at angle theta 28.
devlian [24]

Answer:

μ = 0.109

Explanation:

Draw a free body diagram of the crate.  There are four forces:

Weight force mg pulling down.

Normal force N pushing up.

Applied force P pulling at θ above the horizontal.

Friction force Nμ pushing to the left.

Sum of the forces in the y direction:

∑F = ma

N + P sin θ − mg = 0

N = mg − P sin θ

Sum of the forces in the x direction:

∑F = ma

P cos θ − Nμ = ma

P cos θ − ma = Nμ

μ = (P cos θ − ma) / N

μ = (P cos θ − ma) / (mg − P sin θ)

Given:

P = 585 N

θ = 28.0°

m = 125 kg

a = 3.30 m/s²

μ = (585 cos 28.0° − 125 kg × 3.30 m/s²) / (125 kg × 9.8 m/s² − 585 sin 28.0°)

μ = 0.109

3 0
3 years ago
A force of 100N moves a body on a horizontal frictionless surface when......
zalisa [80]

Answer:

I. Friction force exerted on the body is less than 100N

Explanation:

For  a body to be static, the moving force must be equal to the frictional force. Since the frictional force is a force of opposition. It tends to oppose the moving force acting on an object.

Hence if the moving force is greater than the force of friction, the Force of fiction will not be able to overcome the moving hence the body will tend to move.

Therefore, for a body to move, Fm > Ff or Ff < Ff

Fm is the moving force

Ff is the force of friction

Given

Fm = 100N

For the 100N body to move the frictional force must be less than 100N

4 0
3 years ago
Find your mass if a scale on earth reads 650 N when you stand on it.
dezoksy [38]

Weight = (mass) x (acceleration of gravity) .

On Earth, acceleration of gravity is 9.8 m/s² (rounded) .

                                                    650 N                 = (mass) x (9.8 m/s²)

Divide each side by (9.8 m/s²):    650 N / 9.8 m/s² = mass

                                                     Mass = 66.3 kilograms (rounded)

7 0
3 years ago
Which shows the correct order of processes leading up to the formation of a main sequence star?
Sphinxa [80]
C. Should be the answer it worked for me
8 0
3 years ago
Read 2 more answers
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