1) Endothermic
2) Heat absorbed by reaction = 2511.6J
3)ΔH_rxn = 18.2 kJ/ mol
Explanation:
Mass of KCl = 10.3 g
Moles of KCl = mass of KCl / molar mass of KCl
= 10.3 g / 74.5513 g/mol
=0.138 mol
Mass of water, m = 200 g
Specific heat of water, C= 4.186 Jg^-1°C^-1
T_initial = 22.0C
T_final = 19.0°C
ΔT = T_final - T_initial
=19.0°C - 22.0°C
= -3.0°C
Heat absorbed = Heat released
q_rxn =-q_water
so,
q_water = m CΔT
substitute
q_water = 200g * 4.186J g^-1 °C^-1 *(-3.0°C)
= -2511.6J
Heat absorbed by reaction = 2511.6J
q_rxn = -q_water = 2511.6J
ΔH_rxn = q_rxn /moles of KCl
=2511.6J / 0.138 mol
ΔH_rxn =18.2kJ / mol
The reaction is a endothermic reaction.
Answer:
Molecular Formula, Be3P2. Synonyms. Beryllium phosphide. Beryllium phosphide (BeP2). EINECS 261-137-1. 57620-29-8. 58127-61-0. Molecular Weight.
Molecular Formula: Be3P2
Molecular Weight: 88.98407 g/mol
Structure: Find Similar Structures
PubChem CID: 6453515
Explanation:
Answer:
The pressure of CO2 = 0.48 atm
Explanation:
Step 1: Data given
Kp = 0.23
Step 2: The balanced equation
2NaHCO3(s) ↔ Na2CO3(s) + CO2(g) + H2O(g)
Step 3: Calculate the pressure of CO2
Kp = (p(CO2))*(p(H2O))
For 1 mol CO2 we have 1 mol H2O
x = p(CO2) = p(H2O)
Kp = 0.23 = x*x
x = √0.23
x = 0.48
pCO2 = x atm = 0.48 atm
The pressure of CO2 = 0.48 atm
The answer would possible be letter a
Answer:
Look at the picture.
Explanation:
On stage one binding of a substrate occurs (and also the geometry of active site may change) and water comes to the site. On stage two the hydrolisis takes place and on stage 3 products deabsorb from the enzyme.