In Engineering, the thrust angle is checked by referencing: C. vehicle centerline.
<h3>What is a
thrust angle?</h3>
A thrust angle can be defined as an imaginary line which is drawn perpendicularly from the centerline of the rear axle of a vehicle, down the centerline.
This ultimately implies that, the thrust angle is a reference to the centerline (wheelbase) of a vehicle, and it confirms that the two wheels on both sides are properly angled within specification.
Read more on thrust angle here: brainly.com/question/13000914
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Answer:
E= 15 GPa.
Explanation:
Given that
Length ,L = 0.5 m
Tensile stress ,σ = 10.2 MPa
Elongation ,ΔL = 0.34 mm
lets take young modulus = E
We know that strain ε given as



We know that

Therefore the young's modulus will be 15 GPa.
Answer:
Explanation:
(c). looking for the radiation of the collector is given thus
C = 0.095 + 0.04 sin [360/365(n-100)] = 0.095 + 0.04 sin [360/365(1-100)]
C = 0.05535
∴ Diffuse radiation of the collector Idc = C*Ib + (1+cosσ/2)
Idc = 0.5535 * 908.7 (1+cos40/ 2) = 44.41 W/m²
Idc = 44.41 W/m²
Answer:
the percent increase in the velocity of air as it flows through the dryer is 12%
Explanation:
given data
density of air ρ = 1.18 kg/m³
density of air ρ' = 1.05 kg/m³
solution
we know there is only one inlet and exit
so
ρ × A × v = ρ' × A × v' ........................1
put here value and we get
= 1.12
so the percent increase in the velocity of air as it flows through the dryer is 12%