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evablogger [386]
1 year ago
11

assuming complementary inputs are available, the minimum number of transistors needed to realize a two input xor gate is:

Engineering
1 answer:
babunello [35]1 year ago
4 0

Assuming complementary inputs are available, the minimum number of transistors needed to realize a two input xor gate is 4.

If two inputs work well together in the production process, they are said to be complements. Since the inputs are used in fixed proportions, if the price of one input lowers, more of it will be sought after, increasing the demand for the other input.

In this study, a model of anticompetitive exclusive contracts with complimentary inputs is built. A downstream company converts a variety of complementary inputs into finished goods. When complementary input providers hold a dominant position in a specific input market, upstream competition price within that market benefits both the downstream firm and the complementary inputs providers by driving up complementary input prices.

Thus, even when entry that is socially optimal is permitted, the downstream firm is unable to generate higher profits. Therefore, even in the absence of scale economies, downstream competition, and relationship-specific investment, the inefficient incumbent provider can prevent socially efficient entrance by employing exclusive contracts.

To know more about complementary inputs click on the link:

brainly.com/question/13125554

#SPJ4

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Consider a thin suspended hotplate that measures 0.25 m × 0.25 m. The isothermal plate has a mass of 3.75 kg, a specific heat of
Orlov [11]

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Heat losses by convection, Qconv = 90W

Heat losses by radiation, Qrad = 5.814W

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Heat transfer is defined as the transfer of heat from the heat surface to the object that needs to be heated. There are three types which are:

1. Radiation

2. Conduction

3. Convection

Convection is defined as the transfer of heat through the actual movement of the molecules.

Qconv = hA(Temp.final - Temp.surr)

Where h = 6.4KW/m2K

A, area of a square = L2

= (0.25)2

= 0.0625m2

Temp.final = 250°C

Temp.surr = 25°C

Q = 64 * 0.0625 * (250 - 25)

= 90W

Radiation is a heat transfer method that does not rely upon the contact between the initial heat source and the object to be heated, it can be called thermal radiation.

Qrad = E*S*(Temp.final4 - Temp.surr4)

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= 5.6703 x 10-8 W/m2K4

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7 0
4 years ago
8.26 Three identical fatigue specimens (denoted A, B, and C) are fabricated from a nonferrous alloy. Each is subjected to one of
Elis [28]

Answer:

Fatigue lifetimes will be ranked as B>A>C

Explanation:

Start by calculating the mean stress for all samples

σa= (σamax + σamin)/2 = (450 - 350)/2 = 50MPa

σb= (σbmax + σbmin)/2 = (400 - 300)/2 = 50MPa

σa= (σcmax + σcmin)/2 = (340 - 340)/2 = 0MPa

Now calculate the stress amplitudes of all three samples

σa= (σamax - σamin)/2 = (450 + 350)/2 = 400MPa

σb= (σbmax - σbmin)/2 = (400 + 300)/2 = 350MPa

σc= (σcmax - σcmin)/2 = (340 + 340)/2 = 340MPa

The mean stress of samples A and B is the same which is higher than sample C. Hence samples A and B will have a higher fatigue life than sample C. However, the higher stress amplitude means lower fatigue life, hence, sample B will have a higher fatigue life than sample A. So the order will be B> A> C.

Attached picture shows the justification using and S- N plot.

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