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evablogger [386]
1 year ago
11

assuming complementary inputs are available, the minimum number of transistors needed to realize a two input xor gate is:

Engineering
1 answer:
babunello [35]1 year ago
4 0

Assuming complementary inputs are available, the minimum number of transistors needed to realize a two input xor gate is 4.

If two inputs work well together in the production process, they are said to be complements. Since the inputs are used in fixed proportions, if the price of one input lowers, more of it will be sought after, increasing the demand for the other input.

In this study, a model of anticompetitive exclusive contracts with complimentary inputs is built. A downstream company converts a variety of complementary inputs into finished goods. When complementary input providers hold a dominant position in a specific input market, upstream competition price within that market benefits both the downstream firm and the complementary inputs providers by driving up complementary input prices.

Thus, even when entry that is socially optimal is permitted, the downstream firm is unable to generate higher profits. Therefore, even in the absence of scale economies, downstream competition, and relationship-specific investment, the inefficient incumbent provider can prevent socially efficient entrance by employing exclusive contracts.

To know more about complementary inputs click on the link:

brainly.com/question/13125554

#SPJ4

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A. Name the major strengthening mechanisms in metals and explain the working principle under each mechanism.Give the relevant eq
Sever21 [200]

Answer:

a) Solid solution strengthening and alloying,  Precipitation hardening, work hardening

b) Absence of enough  crystallographic misalignment in the grain boundary region for a small-angle

Explanation:

<u>A) strengthening mechanism</u>

i) Solid solution strengthening and alloying:

In solid solution strengthening and alloying mechanism there is an addition of one atom of solute to another during this process, there might be substitution of interstitial point defect in crystal

also the shear stress required can be represented as:  Δz = Gb√Ce^3/2

where : C = solute concentration , e = strain on material

ii) Precipitation hardening:

During precipitation hardening the alloying above the concentrate will lead to the formation of a second phase also under precipitation hardening a second phase can also be created via thermal treatments

particle bowing cab be written as :  Δz = Gb / L-2x

iii) work hardening :

Dislocation caused by stress fields been generated hardens metals under the work hardening mechanism

dislocation can be represented as ; Gb √ p

where : G = shear modulus , b = Burgess vector, p = dislocation density

B) The small angle grain boundaries are not effective enough because there is less crystallographic misalignment in the grain boundary region for a small-angle

3 0
3 years ago
Poly(cis-1,4-isoprene), or natural rubber (NR), has a tendency crystallize. The Tm of this polymer is slightly below room temper
Nonamiya [84]

Answer:

Explanation:

Crystalline melting temperature (Tm) is termed as the temperature required for a  crystalline polymer to change to a fluid or glasslike crystalline spaces of a semi-crystalline polymer liquefy (expanded sub-atomic movement).  

Crystallization of polymers is an interaction related with incomplete arrangement of their atomic and molecular chains. These chains crease together and structure requested districts called lamellae, which form bigger spheroidal designs named spherulites. Polymers can solidify after cooling from melting, mechanical extending, or dissolvable dissipation. Crystallization influences the optical, mechanical, and synthetic chemical properties of the polymer.  

For a crystalline polymer, a required polymer chain is present in or goes along a few crystalline and amorphous zones. The crystalline zones are comprised of intermolecular & intramolecular arrangements or deliberate and thus firmly stuffed plan of atoms or chain fragments, and an absence of it brings about the development of amorphous zones.  

The mechanical property boundary, for example, shear modulus expansions in the temperature of perception for polymer material framework.  

The temperature reaction of direct linear polymers might be seen as partitioned into three particularly separate fragments:  

1. Above Tm: The polymer stays as fluid whose consistency & viscosity would rely upon atomic molecular weight and temperature.  

2. Between Tm and Tg: This area may go between close to 100% crystalline & 100% amorphous chain atomic bunches relying upon the polymer underlying consistency. The amorphous part carries on similar to supercooled fluid in this section. The generally actual conduct of the polymer in this moderate portion is similar to an elastic rubber.  

3.Below Tg: The polymer material saw as glass is hard and inflexible, showing and emanating a predetermined coefficient of thermal extension. The glass is more like a crystalline strong than the fluid in personal conduct standard regarding mechanical property boundaries. In regard to the molecular atomic request, in any case, the glass all the more intently takes after the fluid. There is little contrast between the direct linear and cross-connected polymer beneath Tg.

8 0
3 years ago
A 35-pound force is applied to a 3-inch cylinder with a 6-inch stroke. What is the power produced by the cylinder that moves its
vampirchik [111]

Explanation:

Power = work / time

Power = force × distance / time

P = (35 lbf) (6 in) / (0.7 s)

P = 300 lbf in/s

7 0
4 years ago
Given the inherent costs of regulation it is safe to say that there is always a negative economic impact associated with regulat
Alexus [3.1K]

the answer is true.                                     <u>                    </u>                                                              

6 0
2 years ago
John Deere invented the phonograph.
Travka [436]
False? i think false yes false
7 0
3 years ago
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