Answer:
(a) The number of gallons of water in the tank when it starts draining.
(b) How many minutes it takes for all of the water to drain from the tank.
Explanation:
So, basically v(t) defines the volume of tank as a function of time. When we evaluate t=0, we find the intercept with the y-axis which represent the initial water volume of the tank in gallons:
now we need to know when v(t)=0, so:
Solving for t:
This represents the amount of time in minutes required to drain all of the water from the tank, in other words v=0gal
I attached a picture where you can see the graph that represents the function:
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Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.
Explanation: <u>Dalton's</u> <u>Law</u> <u>of</u> <u>Partial</u> <u>Pressure</u> states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:
The proportion of each individual gas in the total pressure is expressed in terms of <u>mole</u> <u>fraction</u>:
= moles of a gas / total number moles of gas
The rigid tank has total pressure of 1MPa.
molar mass = 14g/mol
mass in the tank = 2000g
number of moles in the tank: = 142.85mols
molar mass = 44g/mol
mass in the tank = 4000g
number of moles in the tank: = 90.91mols
Total number of moles: 142.85 + 90.91 = 233.76 mols
To calculate partial pressure:
For Nitrogen gas:
= 0.6
For Carbon Dioxide:
0.4
Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.
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