1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gemiola [76]
3 years ago
5

The product life cycle defines the stages that new products move through as they enter, are established in, and ultimately leave

the marketplace. In their life cycles, products pass through four stages: introduction, growth, maturity, and decline. The product life cycle offers a useful tool for managers to analyze the types of strategies that may be required over the life of their products. Even the strategic emphasis of a firm and its marketing mix (4Ps) strategies can be adapted from insights about the characteristics of each stage of the cycle.
Engineering
1 answer:
Bas_tet [7]3 years ago
4 0

Answer:

The four marketing mix of every new business are:

1. Product

2. Place

3. Price

4. Promotion

For each of the stages of product life cycle, those 4p should be use appropriately.

Explanation:

The four marketing mix of every new business are:

1. Product

2. Place

3. Price

4. Promotion

the product life cycle are directly proportional to the 4p of marketing. the product life cycle stages are introduction, growth, maturity and decline.

For each of the stages of product life cycle, those 4p should be use appropriately.

Stages of product life cycle and how the 4p fit into it.

The introduction stage:

at this stage, a new product just want to be introduced to the consumers. the product stage has being developed. The place where the product will fit in will also be consider. the location of people who consume this product. Pricing strategy consider a low price at the introduction stage, the business owner may not get any profit at this stage. then, continuous advertisement to create awareness of the product to the environment.

The growth stage:

the product will continuing to be move to different locations. the standard of the product quality will be maintained. the Pricing will start increasing. then, continuous advertisement to create awareness of the product and working on improving the product to suit the consumer.

the Mature stage:

At this stage, the consumer are fully aware of the product. wide range of location are reach. the pricing has reach its peak. Profit have been maximized. And, competitors of the product are in the market. Corporate social responsibility (CSR) will be the promotional value at this stage.

The Declining stage:

The business product have fully grown to its peak, and its only constant promotional values like CSR, advertisement, bonuses, can sustain it in the market. At this stage also, price comparison with other competitor should be carefully look into.

You might be interested in
Why is oil black and why does oil look black
Rina8888 [55]

Answer:While heat cycles cause oil to darken, soot causes oil to turn black

Explanation:

Most people associate soot with diesel engines, but gasoline engines can produce soot as well, particularly modern gasoline-direct-injection engines. ... Any finer filtration and the filter could catch dissolved additives in the motor oil

4 0
2 years ago
4.68 Steam enters a turbine in a vapor power plant operating at steady state at 560°C, 80 bar, and exits as a saturated vapor at
garik1379 [7]

Answer:

please mark me as a brainleast

Explanation:

hahahahhahaahhahahahahahahahahahahahahahahahaahhhahhhahaahahhaahhhahahaah

3 0
2 years ago
A turbine operates at steady state, and experiences a heat loss. 1.1 kg/s of water flows through the system. The inlet is mainta
strojnjashka [21]

Answer:

\dot W_{out} = 399.47\,kW

Explanation:

The turbine is modelled after the First Law of Thermodynamics:

-\dot Q_{out} -\dot W_{out} + \dot m\cdot (h_{in}-h_{out}) = 0

The work done by the turbine is:

\dot W_{out} = \dot m \cdot (h_{in}-h_{out})-\dot Q_{out}

The properties of the water are obtained from property tables:

Inlet (Superheated Steam)

P = 10\,MPa

T = 520\,^{\textdegree}C

h = 3425.9\,\frac{kJ}{kg}

Outlet (Superheated Steam)

P = 1\,MPa

T = 280\,^{\textdegree}C

h = 3008.2\,\frac{kJ}{kg}

The work output is:

\dot W_{out} = \left(1.1\,\frac{kg}{s}\right)\cdot \left(3425.9\,\frac{kJ}{kg} -3008.2\,\frac{kJ}{kg}\right) - 60\,kW

\dot W_{out} = 399.47\,kW

5 0
3 years ago
Air enters the combustor of a jet engine at p1=10 atm, T1=1000°R, and M1=0.2. Fuel is injected and burned, with a fuel/air mass
snow_lady [41]

Answer:

M2 = 0.06404

P2 = 2.273

T2 = 5806.45°R

Explanation:

Given that p1 = 10atm, T1 = 1000R, M1 = 0.2.

Therefore from Steam Table, Po1 = (1.028)*(10) = 10.28 atm,

To1 = (1.008)*(1000) = 1008 ºR

R = 1716 ft-lb/slug-ºR cp= 6006 ft-lb/slug-ºR fuel-air ratio (by mass)

F/A =???? = FA slugf/slugaq = 4.5 x 108ft-lb/slugfx FA slugf/sluga = (4.5 x 108)FA ft-lb/sluga

For the air q = cp(To2– To1)

(Exit flow – inlet flow) – choked flow is assumed For M1= 0.2

Table A.3 of steam table gives P/P* = 2.273,

T/T* = 0.2066,

To/To* = 0.1736 To* = To2= To/0.1736 = 1008/0.1736 = 5806.45 ºR Gives q = cp(To* - To) = (6006 ft-lb/sluga-ºR)*(5806.45 – 1008)ºR = 28819500 ft-lb/slugaSetting equal to equation 1 above gives 28819500 ft-lb/sluga= FA*(4.5 x 108) ft-lb/slugaFA =

F/A = 0.06404 slugf/slugaor less to prevent choked flow at the exit

5 0
3 years ago
Gas is kept in a 0.1 m diameter cylinder under the weight of a 100 kg piston that is held down by a spring with a stiffness k =
Artyom0805 [142]

Answer:

The spring is compressed by 0.275 meters.

Explanation:

For equilibrium of the gas and the piston the pressure exerted by the gas on the piston should be equal to the sum of  weight of the piston and the force the spring exerts on the piston

Mathematically we can write

Force_{pressure}=Force_{spring}+Weight_{piston}

we know that

Force_{pressure}=Pressure\times Area=300\times 10^{3}\times \frac{\pi \times 0.1^2}{4}=750\pi Newtons

Weight_{piston}=mass\times g=100\times 9.81=981Newtons

Now the force exerted by an spring compressed by a distance 'x' is given by Force_{spring}=k\cdot x=5\times 10^{3}\times x

Using the above quatities in the above relation we get

5\times 10^{3}\times x+981=750\pi \\\\\therefore x=\frac{750\pi -981}{5\times 10^{3}}=0.275meters

5 0
3 years ago
Other questions:
  • A cylindrical specimen of brass that has a diameter of 20 mm, a tensile modulus of 110 GPa, and a Poisson’s ratio of 0.35 is pul
    13·1 answer
  • What is EL Niño?
    9·1 answer
  • Technician A says ASE certification is mandatory in all 50 states before performing an automotive repair for pay. Technician B s
    12·1 answer
  • How do you calculate the dynamic lift in an aeroplane?
    5·1 answer
  • Sam promises to pay Sandy $2,000 in four years and another $3,000 four years later for a loan of $2,000 from Sandy today. What i
    8·1 answer
  • An open vat in a food processing plant contains 500 L of water at 20°C and atmospheric pressure. If the water is heated to 80°C,
    9·1 answer
  • 6. What symptom will be exhibited on an engine equipped with a pneumatic governor system if the cooling fins
    14·1 answer
  • What is this i dont understand this at all
    9·1 answer
  • (CO 3) A nonrecursive filter may best be described as _____. Group of answer choices a filter whose current output depends on pa
    13·1 answer
  • Agricultural economics is a study of how agriculture and business are related.<br> False<br> True
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!